Answers are:
1) ΔH is negative because that is combustion reaction and heat is released, enthalpy of combustion is -2877.5 kJ/mol.
2) ΔS is positive, because there more molecules on the right side of balanced chemical reaction, standard molar entropy is <span>310.23 J/mol</span>·<span>K.
</span>3) ΔG = ΔH - TΔS.
ΔG = -2877.5 kJ/mol - 298 K · 310.23 J/mol·K.
ΔG = -2969.95 kJ/mol.
Answer:
Yes
Explanation:
They are a unique type of eukaryote because they lack an important organelle: mitochondria. Mitochondria are essential for producing cellular energy in most eukaryotic cells. However, due to its habitat, it is able to acquire energy from a process called sulfur mobilization.
They are significant because they challenge the idea that eukaryotes need mitochondria to be classified as eukaryotic. However, they have other membrane-bound organelles such as a nucleus and Golgi apparatus, meaning they remain eukaryotic.
Research suggest they lost their mitochondria over time, rather than never having had them throughout their ancestry.
Because of all these reasons, they still meet the definition of a eukaryote.
Given:
Sulfur dioxide and dihydrogen sulfide system
Vapor Pressure of water, H2O = 23 torr
P_SO2 = P_H2S
Temperature of the system = 298 K
Assume: Total pressure of the system is 1 atm = 760 torr
If partial pressure of SO2 is equal to the concentration of H2S, then,
760 = 0.5*PSO2 + 0.5PH2S
760 = PSO2
Answer:
The plants at a light intensity of 1200 will produce more oxygen than the plants at 400.
Explanation: