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kirill [66]
4 years ago
3

The force of gravity between two objects: The force of gravity between two objects: depends on the density, not the mass of the

bodies. depends on the temperature, density, and size of the bodies. increases with the masses of the bodies, but decreases with their separations. increases with the square of their masses, but decreases with the cube of their periods of orbit about the Sun. increases with the masses of the bodies, but decreases with the square of the distances between them.
Physics
1 answer:
Svetllana [295]4 years ago
3 0
<h2>Answer: increases with the masses of the bodies, but decreases with the square of the distances between them.</h2>

According to Newton's law of Gravitation, the force F exerted between two bodies or objects of masses m1 and m2  and separated by a distance r  is equal to the product of their masses divided by the square of the distance:

F=G\frac{(m1)(m2)}{r^2}

Where Gis the gravitational constant.

As we can see, this force is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

This means that the gravity force decreases when the distance between these two bodies increases, and increases when the masses of the bodies increases.

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An electromagnetic wave with high frequency and high energy is A. Safe for humans. B. Is helpful to humans. C. Is helpful to hum
Vilka [71]
B and C are both correct choices.
4 0
4 years ago
A ball is rolled at an initial speed of 5 m/s and finishes a certain distance at a speed of 7 m/s. if the ball rolled for 9 seco
Setler79 [48]

Answer:

The ball rolled a distance of 54 m.

Explanation:

Given:

Initial velocity of the ball is, u=5\ m/s

Final velocity of the ball is, v=7\ m/s

Time for rolling is, t=9\ s

The distance of rolling is, S=?

First, let us find the acceleration of the ball using Newton's equation of motion as:

v=u+at\\a=\frac{v-u}{t}\\a=\frac{7-5}{9}=\frac{2}{9}\ m/s^2

Now, displacement of the ball can be determined using the following equation of motion:

v^2=u^2+2aS

Rewriting the above in terms of 'S', we get

S=\frac{v^2-u^2}{2a}

Plug in the known values and solve for 'S'. This gives,

S=\frac{7^2-5^2}{2\times \frac{2}{9}}\\\\S=\frac{49-25}{\frac{4}{9}}\\\\S=\frac{9\times 24}{4}\\\\S=9\times 6=54\ m

Therefore, the ball rolled a distance of 54 m.

3 0
4 years ago
A blue car pulls away from a red stop-light just after it has turned green with a constant acceleration of 0.2 m/s2. A green car
jolli1 [7]

Answer:

After 15 seconds, the green car will catch up with the blue car

Explanation:

Let the time for the green car to catch up with the blue car be T

When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal

Distance covered by blue car after time T is given by: s = ut + 0.5 at²

Where u = 0, a = 0.2 m/s², t = T

S = 0.5 × 0.2 × T² = 0.1 T²

Velocity of blue car, v = u+ at

v = 0.2T

Distance covered by green car at T is given as: S = Velocity × time

Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)

S = 0.2T (T - 7.5)

S = 0.2 T² - 1.5T

Equating the distance covered by the two cars

0.2T² - 1.5T = 0.1T²

0.1T² - 1.5T = 0

T(0.1T - 1.5) = 0

T = 0 or

T = 1.5/0.1 = 15 secs

Therefore, after 15 seconds, the green car will catch up with the blue car

8 0
3 years ago
If astronaut A(90kg) and astronaut B(110kg) are linked by 9.5m of rope and the centre of mass is 5.2m from astronaut A. What is
sergij07 [2.7K]
You can't tell from that information. The center of mass is ALWAYS there, and it has nothing to do with how they're moving.
3 0
4 years ago
Uveďte príklady nesúhlasnej alebo nejednoznačnej komunikácie?
umka2103 [35]

Answer:hiuwiauwney jejjksuu

Explanation:

5 0
3 years ago
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