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77julia77 [94]
3 years ago
15

Uveďte príklady nesúhlasnej alebo nejednoznačnej komunikácie?

Physics
1 answer:
umka2103 [35]3 years ago
5 0

Answer:hiuwiauwney jejjksuu

Explanation:

You might be interested in
5. How much time does it take for a bird flying at a speed of 45 kilometers per hour to travel a
Lyrx [107]

Answer:

40h

Explanation:

Use the velocity formula to solve

v = \frac{d}{t}

In this question, you are given velocity v = 45km/h, and you are given a distance, d = 1800km.  Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

v = \frac{d}{t}

Start by multiplying both sides by t

v(t) = \frac{d}{t}(t)\\\\vt = d

Then divide both sides by v.

vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}

Now that you've isolated for time, sub in your values and calculate.

t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h

8 0
2 years ago
How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?
inysia [295]

1 coulomb of electric charge is carried by  6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

         (2.0 x 10^20) / (6.25 x 10^18 x 10)    sec  =  <em>3.2 seconds</em>


6 0
3 years ago
How do modern scientists describe the make up of matter
mojhsa [17]
<span>Matter is considered by modern scientists to be anything in the universe that takes up mass. It can be in any state including solid, liquid, or gas. It can also hold potential and or kinetic energy.</span>
4 0
4 years ago
Uveďte príklady nesúhlasnej alebo nejednoznačnej komunikácie?
umka2103 [35]

Answer:hiuwiauwney jejjksuu

Explanation:

5 0
3 years ago
An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the ob
lorasvet [3.4K]

Answer:

the force of attraction between the two charges is 3.55 N.

Explanation:

Given;

first charge carried by the object, q₁ = 15.5 µC

second charge carried by the q₂ = -7.25 µC

distance between the two charges, r = 0.525 m

The force of attraction between the two charges is calculated as;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N

Therefore, the force of attraction between the two charges is 3.55 N.

3 0
3 years ago
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