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umka21 [38]
3 years ago
15

How many years can it take plastic bottle to break down?

Chemistry
1 answer:
kkurt [141]3 years ago
4 0
Depending on the bottle but on average 450 years
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C). If 0.5 mole of oxygen (,) reacted with hydrogen (H2), how many mole of water (H20) was produced
son4ous [18]

Answer:

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

4 0
3 years ago
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Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant f
umka21 [38]

Answer:

1) 0.00498 mol Cu.

2) 0.00000374 mol CO₂

Explanation:

Question 1)

We want to convert 3.00 * 10²¹ copper atoms into moles. Note that 3.00 is three significant figures.

Recall that by definition, one mole of a substance has exactly 6.022 * 10²³ amount of that substance. In other words, we have the ratio:

\displaystyle \frac{1\text{ mol}}{6.022\times 10^{23} \text{ Cu}}

We are given 3.00 * 10²¹ Cu. To cancel out the Cu, we can multiply it by our above ratio with Cu in the denominator. Hence:

\displaystyle 3.00 \times 10^{21} \text{ Cu} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} \text{ Cu}}

Cancel like terms:

=\displaystyle 3\times 10^{21} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} }

Simplify:

\displaystyle  = \frac{3\text{ mol Cu}}{6.022 \times 10^{2}}

Use a calculator:

= 0.004981... \text{ mol Cu}

Since the resulting answer must have three significant figures:

= 0.00498\text{ mol Cu}

So, 3.00 * 10²¹ copper atoms is equivalent to approximately 0.00498 moles of copper.

Question 2)

We want to convert 2.25 * 10¹⁸ molecules of carbon dioxide into moles. Note that 2.25 is three significant digits.

By definition, there will be 6.022 * 10²³ carbon dioxide molecules in one mole of carbon dioxide. Hence:

\displaystyle \frac{6.022 \times 10^{23} \text{ CO$_2$}}{1\text{ mol CO$_2$}}

To cancel the carbon dioxide from 2.25 * 10¹⁸, we can multiply it by the above ratio with the carbon dioxide in the denominator. Hence:

\displaystyle 2.25\times 10^{18} \text{ CO$_2$} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23} \text{ CO$_2$}}

Cancel like terms:

\displaystyle= 2.25\times 10^{18} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23}}

Simplify:

\displaystyle = \frac{2.25 \text{ mol CO$_2$}}{6.022\times 10^5}}

Use a calculator:

=0.000003736...\text{ mol CO$_2$}

Since the resulting answer must have three significant figures:

= 0.00000374\text{ mol CO$_2$}

So, 2.25 * 10¹⁸ molecules of carbon dioxide is equivalent to approximately 0.00000374 moles of carbon dioxide.

4 0
3 years ago
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Determine from the balanced chemical reaction if
djyliett [7]

Answer:Correct

Explanation:According to the balanced chemical reaction, 2 mol FeBr3 are consumed for every 3 mol Na2S consumed.

7 0
2 years ago
I need help <br> Please help me lol
Lyrx [107]
It’s very very blurry
3 0
3 years ago
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What is the unit of temperature on a solubility graph
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Answer:

Khfxgkhxxkfhkugxxiufxhfixiyf

Explanation:

Xlufy8fxtukuxfxtu

6 0
3 years ago
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