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salantis [7]
3 years ago
14

A 0.50-mm-diameter hole is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m

behind the slit?
Physics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

w=4.88*10^{-3}m\\or\\w=4.88mm

Explanation:

Given data

Diameter D=0.50 mm

Wavelength λ=500 nm

Length L=2.0 m

To find

Width w

Solution

Circular aperture of diameter D will have bright central maximum of diameter:

w=(2.44λL)/D

w=(\frac{2.44(500*10^{-9}m )(2.0m)}{0.50*10^{-3}m} )\\w=4.88*10^{-3}m\\or\\w=4.88mm

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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 j electrical energy is
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Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.

To run the fan, electrical energy is utilized.

Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.

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The force that causes an impulse and a force that causes a change in momentum are?
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A horse of mass 242 kg pulls a cart of mass 224 kg. The acceleration of gravity is 9.8 m/s 2 . What is the largest acceleration
Rufina [12.5K]

To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as

F = ma

Where,

m= Mass

a = Acceleration

At the same time the frictional force can be defined as,

F_f = \mu N

Where,

\mu = Frictional coefficient

N = Normal force (mass*gravity)

Our values are given as,

m_h = 242 kg\\m_c = 224 kg\\\mu = 0.894\\

By condition of Balance the friction force must be equal to the total net force, that is to say

F_{net} = F_f

m_{total}a = \mu m_hg

(m_h+m_c)a = \mu*m_h*g

Re-arrange to find acceleration,

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a = 4.54 m/s^2

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