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salantis [7]
3 years ago
14

A 0.50-mm-diameter hole is illuminated by light of wavelength 500 nm. What is the width of the central maximum on a screen 2.0 m

behind the slit?
Physics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

w=4.88*10^{-3}m\\or\\w=4.88mm

Explanation:

Given data

Diameter D=0.50 mm

Wavelength λ=500 nm

Length L=2.0 m

To find

Width w

Solution

Circular aperture of diameter D will have bright central maximum of diameter:

w=(2.44λL)/D

w=(\frac{2.44(500*10^{-9}m )(2.0m)}{0.50*10^{-3}m} )\\w=4.88*10^{-3}m\\or\\w=4.88mm

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