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kobusy [5.1K]
3 years ago
10

The sprinter experiences ___________ from A to B to C.

Physics
2 answers:
Trava [24]3 years ago
5 0

motion from A to B to C.....

Nitella [24]3 years ago
4 0
The sprinter experiences distance from A to B to C
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A rod of length L is hinged at one end. The moment of inertia as the rod rotates around that hinge is ML2 /3. Suppose a 2.00-m r
Stels [109]

To solve this problem we will apply the concepts related to the moment of inertia and Torque, the latter both its translational and rotational expression.

According to the information given the moment of inertia of the body would be

I = \frac{1}{3} mL^2

Replacing we have

I = \frac{1}{3} (3kg)(2m)^2

I = 4 kg * m^2

Now the translational torque would be the product between the force applied (Its own Weight) and the distance (Its center of mass at the middle)

\tau = F*r

\tau = mg (\frac{L}{2})

\tau = (3)(9.8)(\frac{2}{2})

\tau = 29.4N\cdot m

Now the rotational torque is defined as the product between the moment of inertia and the angular acceleration, then,

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

Replacing,

\alpha = \frac{29.4}{4}

\alpha =7.35 rad / s^2

Therefore the angular acceleration is 7.35rad/s^2

4 0
3 years ago
Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, a
Blababa [14]

Answer: c a d b

Explanation:

4 0
3 years ago
A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
krok68 [10]

Answer:

The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

8 0
4 years ago
A screen is placed 1.60 m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40 c
Lunna [17]

Answer:

distance between the two second-order minima is 2.8 cm

Explanation:

Given data

distance = 1.60 m

central maximum = 1.40 cm

first-order diffraction minima = 1.40 cm

to find out

distance between the two second-order minima

solution

we know that fringe width = first-order diffraction minima /2

fringe width = 1.40 /2 = 0.7 cm

and

we know fringe width of first order we calculate slit d

β1 = m1λD/d

d = m1λD/β1

and

fringe width of second order

β2 = m2λD/d

β2 = m2λD / ( m1λD/β1 )

β2 = ( m2 / m1 ) β1

we know the two first-order diffraction minima are separated by 1.40 cm

so

y = 2β2 = 2 ( m2 / m1 ) β1

put here value

y = 2 ( 2 / 1 ) 0.7

y = 2.8 cm

so distance between the two second-order minima is 2.8 cm

6 0
3 years ago
Band of which of these colours are not seen in a spectrum
Ede4ka [16]
The only colours that are in the spectrum are red, orange, yellow, green, blue, indigo and violet. hope this helps!
7 0
3 years ago
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