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kiruha [24]
3 years ago
8

About how many times greater is the density of a neutron star compared to a white dwarf?

Physics
1 answer:
irina1246 [14]3 years ago
7 0

Answer:

Explanation:

over a million times

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In order to identify them, animal fossils and other fossils nearby can be: A. compared B. piled C. seen
tigry1 [53]

Answer:

A.compared

Explanation:

Fossils help figure out the time that organisms lived. If you know one of the fossils, it can be used as a reference for others around.

5 0
3 years ago
This technique allowed multiple peoples DNA to be compared to look for
Lady_Fox [76]

DNA sequencing is the technique which allows multiple peoples DNA to be compared to look for similarities and differences in order to solve crime and is denoted as option C.

<h3>What is DNA?</h3>

This is referred to as the deoxyribonucleic acid and contains the genetic components of organisms and is also located in the nucleus. On the other hand, DNA sequencing refers to the process of determining the nucleic acid sequence.

Each organisms has a unique DNA sequence which is why it is used to identify individuals through the use of bodily fluids such as saliva, blood etc.

It is used to compare the similarities and differences in order to solve crime thereby making it the most appropriate choice.

Read more about DNA sequencing here brainly.com/question/1243987

#SPJ1

7 0
1 year ago
What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
Yuki888 [10]

Explanation:

825m/s / 1.8Hz = 458.33m

6 0
2 years ago
Read 2 more answers
The police car with its 300-Hz siren is moving away from the warehouse at a speed of 16.0 m/s . . . What frequency does the driv
bazaltina [42]
Frequency heard by listener: fl = ? 
frequency of source: fs = 300 Hz 
velocity of listener: vl = 16 m/s 
velocity of source: vs = 0 
<span>velocity of sound in air: c = 344 m/s 

</span><span>fl = fs [(c – vl)/c] = 300[(344-16)/344]
</span>        =286.04 Hz
8 0
3 years ago
Read 2 more answers
A monochromatic red laser beam emitting 1 mW at a wavelength of 638 nm is incident on a silicon solar cell. Find the following:
tia_tia [17]

Answer:

Explanation:

First we calculate the energy of the photon

E=(Planck constant × speed of light in vacuum)÷ wave length

E=\frac{6.626*10^{34}*2.998*10^{8}  }{638*10^{-9} } = 3.114*10^{49}

Next we find the total energy per second

total energy= 1*10^{-3}W *\frac{1JS^{-1} }{1W}  = 1*10^{-3} JS^{-1}

Next we calculate the number the photon per second

= total energy ÷ energy of 1 photon

= \frac{1*10^{-3} JS^{-1}  }{3.114*10^{49} } =  3.21*10^{-53}  \ photons/sec

8 0
3 years ago
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