a 10 kg block reaches a point with a velocity of 15 m per second and slides down a rough track my the coefficient of the kinetic energy between the two surface ab and the block iis0.52
At the end of the baseball bat, because with the length of the bat he had a longer reach and the end of the bat was moving faster than his hands were
0.2 is the value of coefficient of friction (k)
F=kN
F=horizontal force
n=Normal Force
k=coefficient of friction
k=F/N
k=200/1000
k=0.2
The ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them is known as the friction coefficient. Usually, the Greek letter mu is used to indicate it .N is the normal force, and F is the frictional force, hence F = N/N.
Due to the fact that both F and N are measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds). The coefficient of friction can have a variety of values for both static and dynamic friction. Static friction occurs when an object encounters friction that resists any applied force, keeping the object at rest until the static frictional force is released. In kinetic friction, the frictional force resists the motion of the object.
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The bouncy ball experiences the greater momentum change.
To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.
The putty and the ball have the same mass, and you throw them
with the same speed. So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".
After they both hit the wall:
-- The putty has zero momentum.
Its momentum changed by an amount of M .
-- The ball has momentum of " M in the direction away from the wall ".
Its momentum changed by an amount of 2M .
Answer with Explanation:
We are given that
Distance,r=0.27 m
Tangential speed=v=0.49 m/s
a.Angular speed ,
Using the formula
Time period,
b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m
c.Maximum speed,
d.Maximum acceleration=
