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shusha [124]
3 years ago
12

A gnat takes off from one end of a pencil and flies around erratically for 41.641.6 s before landing on the other end of the sam

e pencil. If the gnat flew a total distance of 6.656.65 m, and the pencil is 0.04630.0463 m long, find the gnat's average speed and the magnitude of the gnat's average velocity.
Physics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

average speed  is 0.159 m/s

average velocity = 0.0011 m/s

Explanation:

given data

time = 41.6 s

total distance = 6.65 m

length = 0.0463 m

to find out

average speed and the magnitude average velocity

solution

we know average speed formula is

average speed = \frac{total distance}{total time}   ...............1

put here value

average speed = \frac{6.65}{41.6}

average speed  is 0.159 m/s

and

average velocity formula is

average velocity = \frac{displacement}{total time}   ...............2

here displacement is initial point to final point and here is 0.0463 m

put here value

average velocity = \frac{0.0463}{41.6}

average velocity = 0.0011 m/s

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Answer:

v_x=34 m/s

v_y=53.9\ m/s

Explanation:

<u>Horizontal Launch</u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

v_y=g.t

The horizontal component of the velocity is always the same:

v_x=34 m/s

The vertical component at t=5.5 s is:

v_y=9.8*5.5=53.9

v_y=53.9\ m/s

8 0
2 years ago
How is sound intensity measured?
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Answer:

Sound intensity is measured with a sound level meter or Sound pressure Level (SPL) Meter.

Explanation:-

It measure sound intensity is the sound pressure level. The unit of measurement is decibels.

7 0
2 years ago
PRACTICE ANOTHER A cube of wood having an edge dimension of 19.7 cm and a density of 647 kg/m3 floats on water. (a) What is the
dedylja [7]

CHECK COMPLETE QUESTION

The cube of wood having an edge dimension of 19.7cm and a density of 647kg/m3 floats on water

(a) What is the distance from the horizontal top surface of the cube to the water level answer in cm

(b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface answer in kg

Answer:

a)6.29cm

b)2.78 kg

Explanation:

Given:

Let us calculate the volume first, we were given dimension as 19.7cm=0.197m

Volume is (0.197 meters)³ = 0.00764m³

Then we can calculate the mass as;

Given mass is 647 kg/m³ x 0.00774m³ = 4.947kg

The weight = mass × acceleration due to gravity

weight = 4.947 x 9.8 N/kg = 48.44N

By Floating we can say the the buoyancy force has to equal the weight (48.44 N) which has

which is equal to the weight of volume of the displaced water. Or the mass, the calculation is the same.

We know that density of fresh water at 20ºC is 998 kg/m³

Then we can calculate the volume of displaced water as

4.947 kg / 998 kg/m³ = 0.00496 m³

We know that the displaced water has a shape of a rectangular solid with 0.197 meters on the two horizontal dimensions, and h as the height to the surface then

V = 0.197²h = 0.00496

0.00496= 0.197²h

h = 0.1278 meters or 12.78 cm

Then the the distance exposed, would be 19.7–12.78 = 6.29 cm

b) ifthe cube is fully submerged, the volume of the displaced water is 0.00774m³

mass of displaced water is 0.00774m³ x 998 kg/m³ = 7.724 kg

Added mass is the mass of the displaced water – mass of block

= 7.724–4.947 = 2.78 kg

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The flat sheet of paper has more surface area than the crumpled ball
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Answer:

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hope it helps, please give me brainliest.

8 0
2 years ago
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