The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.
<h3> What is scientific notation?</h3>
Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.
You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .
<h3>Why it is used? </h3>
There are two reasons to use scientific notation.
- The first is to reveal honest uncertainty in experimental measurements.
- The second is to express very large or very small numbers so they are easier to read.
Given,
= 6.0 x 10^3- 2.3 × 10^3
= (6.0 - 2.3) × 10^3
= 3.7 × 10^3
Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.
learn more about scientific notation :
brainly.com/question/18073768
#SPJ1
Answer:
okay let me know when i can help, ill be happy too help
Answer:
Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.
Molarity is the molar concentration of the solute dissolved in a volume of a solution. The molarity of the solution prepared by dissolving barium chloride will be 0.085 M.
<h3>What is molarity?</h3>
Molarity is the ratio of the moles of the solute to that of the volume of the solution in Liters. It can be given as,

Here, moles of the barium chloride can be given by the mass and the molar mass and volume is given as 0.450 L.
Substituting values in the equation:

Therefore, 0.085 M barium chloride is the molar concentration.
Learn more about molarity here:
brainly.com/question/26873446
Answer:
See explanation
Explanation:
The particular reactants in the Fischer esterification reaction were not stated.
Generally, a Fischer esterification is a reaction that proceeds as follows;
RCOOH + R'OH ⇄RCOOR' + H2O
This reaction occurs in the presence of an acid catalyst.
We can shift the equilibrium of this reaction towards the products side in two ways;
I) use of a large excess of either of the reactants
ii) removal of one of the products as it is formed.
Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.