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3 years ago

If the forces acting on an object are balanced, what must be true about the motion of this object?

Physics

2 answers:

Novay_Z [31]3 years ago

8 0

D it must have a constant velocity or it would not be balanced

Leokris [45]3 years ago

5 0

Answer:

D Constant velocity

Explanation:

if it has forces moving on it it has constant velocity

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What happens when charged object is brought near uncharged object?<br> Attract or Repel ?

Makovka662 [10]

When a charged object is brought near to but does not touch a neutral object, it causes the side of the neutral object that the charged object is near to become the other charge. It causes charge migration within the neutral object so the two charges (positive and negative) move to opposite sides of the object. Because the two objects do not touch, they do not repel each other, but rather have a slight attraction because of charge migration. If the two object were to touch then they would repel.

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3 years ago

Read 2 more answers

Which one is true ?????

maria [59]

Answer:

b. horizontal distance/time graph

Explanation:

d is incorrect because object is moving at the same pace the entire time

7 0

3 years ago

Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li

diamong [38]

So to solve this problem, we must convert units and then cancel units simultaneously:

$(\frac{982,080,000ft}{s})*(\frac{32,000,000s}{1})*(\frac{12inches}{1ft})=3.77x10^{17} inches$

Therefore we know that the distance that light travels in one year is $3.77x10^{17}$ inches.

7 0

4 years ago

If a wave has a frequency of 6 waves per second and a wavelength of 10 m, what is the wave's speed?

meriva

0.6 is the answer
Hope this helped

6 0

3 years ago

How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees

Nadusha1986 [10]

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

$\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad$

Time of motion is calculated as;

$time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms$

Therefore, the time of motion of the ball is 6.89 ms.

3 0

3 years ago