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Lorico [155]
3 years ago
13

In an oxidation-reduction reaction, the reducing agent In an oxidation-reduction reaction, the reducing agent gains electrons an

d loses potential energy. loses electrons and loses potential energy. gains electrons and gains potential energy. loses electrons and gains potential energy.
Chemistry
1 answer:
Leto [7]3 years ago
8 0

Answer:

loses electrons and loses potential energy.

Explanation:

A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.

Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.

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What mass of Ca(NO3)2 is equal to 0.75 moles of this substance?
sattari [20]

Answer:

Ca - 63.546 g

2N - 28.014 g

2O3 - 96 g

Ca(NO3)2 = 187.56 g

187.56 g x 0.75 mol = 140.67 g

Explanation:

Hope this helps

5 0
3 years ago
Help me with this question?!!​
olya-2409 [2.1K]

Answer:

500 mL

Explanation:

Step 1: Find conversions

1 mL = 0.0338 oz

Step 2: Use Dimensional Analysis

16.9 \hspace{2} oz(\frac{1 \hspace{2} mL}{0.0338 \hspace{2} oz} ) = 500 mL

3 0
3 years ago
Help with this please
Len [333]

Answer:

12

Explanation:

There are 4 sulfur atoms in SO4

4×3=12

This means that it turns into 3×(SO4)

=3SO4

6 0
3 years ago
You observe 2 waves named alpha and beta. The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz. Base
MAVERICK [17]

Answer:

shorter wavelength = alpha wave

Explanation:

Given that,

The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz.

We need to compare the wavelengths of these two waves.

For alpha wave,

\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{5}\\\\=6\times 10^7\ m

For beta wave,

\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{2}\\\\=15\times 10^7\ m

From the above calculations, we find that the wavelength of the alpha wave is shorter than the wavelength of the beta wave.

8 0
3 years ago
Predict what will be observed in each experiment below. experiment predicted observation.
irga5000 [103]

Answer:

The correct answer is -

1.  a) The bubbles will shrink, some may vanish.

2. a) Can A will make a louder and stronger fizz than can B.

Explanation:

In the first question, it is given that the bottle is not opened and therefore, squeezing the bottle filled with a carbonated drink will increase the pressure on the carbonated liquid which forces the bubbles to dissolve or displace or vanish as it moves to empty space.

Thus, the correct answer would be - The bubbles will shrink, some may vanish

In the second question, there are two different conditions for two different unopened cans of carbonated water that are different temperatures one at the garage with higher temperature and one in the fridge at low temperature. As it is known that higher the temperature less will be solubility of gas in liquid so gas in can A will be less soluble which means it has more gas and it will make louder and stronger fizz than B which was stored at low temperature.

thus, the correct answer would be - Can A will make a louder and stronger fizz than can B.

8 0
2 years ago
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