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Lorico [155]
3 years ago
13

In an oxidation-reduction reaction, the reducing agent In an oxidation-reduction reaction, the reducing agent gains electrons an

d loses potential energy. loses electrons and loses potential energy. gains electrons and gains potential energy. loses electrons and gains potential energy.
Chemistry
1 answer:
Leto [7]3 years ago
8 0

Answer:

loses electrons and loses potential energy.

Explanation:

A reducing agent looses electrons in an oxidation-reduction reaction. Oxidation is defined as the loss of electrons.

Reducing agents are oxidized in an oxidation-reduction reaction. When a specie looses electrons, it also looses energy. Hence the answer given above.

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Natalka [10]

The maximum amount of XeF4 that could be produced is 0.5 moles.

XeF4 = Xe (g) 2 F2 (g) (g)

Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.

<h3>What is mole ratio?</h3>

The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.

A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.

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6 0
2 years ago
Is water wet????????????????
PilotLPTM [1.2K]

Answer:

no it is dry_____________

6 0
3 years ago
Read 2 more answers
Anyone know ?? I need help with this
nevsk [136]

Answer:

A

Explanation:

Because the amount of electrons in the outer shell can be a maximum of 8

Hope this helps

6 0
2 years ago
A hydrate is compound that included water molecules within its crystal structure. During an experiment to determine the percent
stellarik [79]

Answer:

The percent by mass of water in this crystal is:

  • <u>21.4%</u>

Explanation:

This exercise can be easily solved using a simple rule of three where the initial weight of the hydrated crystal (6,235 g) is taken into account as 100% of the mass, and the percentage to which the mass of 4.90 g corresponds (after getting warm). First, the values and unknown variable are established:

  • 6,235 g = 100%
  • 4.90 g = X

And the value of the variable X is found:

  • X = (4.90 g * 100%) / 6,235 g
  • X = approximately 78.6%.

The calculated value is not yet the percentage of the water, since the water after heating the glass has evaporated, therefore, the remaining percentage must be taken, which can be calculated by subtraction:

  • Water percentage = Total percentage - Percentage after heating.
  • <u>Water percentage = 100% - 78.6% = 21.4%</u>
4 0
3 years ago
Read 2 more answers
What is the empirical formula for propene C3H6
USPshnik [31]

The empirical formula is the simplest formula attainable while maintaining the ratio so it will be CH2.

Explanation:

The empirical formula of a chemical compound is the simplistic positive integer ratio of atoms being in a compound. A simple example of this thought is that the empirical formula of sulfur monoxide, or SO, would simply be SO, as is the empirical formula of disulfur dioxide, S2O2.

3 0
3 years ago
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