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Marina86 [1]
3 years ago
8

Write the point-slope form, then use that to write the slope-intercept form of the equation

Mathematics
1 answer:
Mashcka [7]3 years ago
7 0
For a line with slope m that passes through a point (x_1, y_1), the point-slope form equation is the following.

y-y_1=m(x-x_1)

We have a given slope of 4 and a given point of (7,5). Now, plug in the values.

\boxed{y-5=4(x-7)}

That is the point-slope form of the line. Now, let's change this into slope-intercept form. Slope-intercept form looks like the following:

y=mx+b

Where m is the slope and b is the y-intercept. Let's do some algebra on our point-slop form equation to change it into slope-intercept form.

y-5=4(x-7)

This was our equation. Let's use the distributive property on 4(x-7).

y-5=4x-28

Now, add 5 to both sides of the equation

\boxed{y=4x-23}

This the slope-intercept form of the line. Thus, we have solved for both the point-slope form and the slope-intercept form. Hope this helps! :)
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Answer:

b. 61.75

Step-by-step explanation:

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1. Rectangle

You can see that the side lengths are 7 and 6.5, so the area is 7 * 6.5 = 45.5

2. Triangle

You know that the base is 6.5 and that the height is 5 (because 12 - 7 = 5) so you can find the area by doing 6.5 * 5 / 2 = 16.25

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Assumed 73.6cm is the hypotenuse.

a^{2} + b^{2} = c^{2}
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Assumed 73.6cm is not the hypotenuse.
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Step-by-step explanation:

As given,

the expression - 3x + 2

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