Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).
- (1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:
![p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL](https://tex.z-dn.net/?f=p_%7BA%7D%20%3D9.98g%2F10.00mL%3D0.998g%2FmL%5C%5Cp_%7BB%7D%20%3D15.61g%2F15.00mL%3D1.041g%2FmL%5C%5Cp_%7BC%7D%20%3D25.65g%2F25.00mL%3D1.026g%2FmL)
- (2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):
![p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3} \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL](https://tex.z-dn.net/?f=p_%7Baverage%7D%3D%5Cfrac%7Bp_%7B1%7D%2Bp_%7B2%7D%2Bp_%7B3%7D%7D%7B3%7D%20%20%20%5C%5Cp_%7Baverage%7D%3D%5Cfrac%7B%280.998%2B1.041%2B1.026%29g%2FmL%7D%7B3%7D%5C%5Cp_%7Baverage%7D%3D1.022g%2FmL)
- (3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:
%error=![\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100](https://tex.z-dn.net/?f=%5Cfrac%7B%7Cp_%7Baverage%7D-p_%7Btheoretical%7D%7C%7D%7Bp_%7Btheoretical%7D%7D%20%2A100)
%error=![\frac{|1.022g/mL-0.997655g/mL|}{0.997655g/mL}*100](https://tex.z-dn.net/?f=%5Cfrac%7B%7C1.022g%2FmL-0.997655g%2FmL%7C%7D%7B0.997655g%2FmL%7D%2A100)
%error=2.44 %
No one can do that by him or her self
Answer ; The correct answer is : 346 m/s .
Sound is a type of longitudinal wave , which is produced when a matter compress or refracts .
Speed of sounds depends on factors like medium , density , temperature etc .
Effect of Temperature on speed of sounds :
When the temperature increases , molecules gains energy and they starts vibrating and with higher temperature vibration becomes fast . So the waves of sounds can travel faster due to faster vibrations . Hence , speed of sounds is directly proportional to the temperature or speed of sounds increases with increase in temperature .
The speed of sounds at 0⁰C is 331 ![\frac{m}{s}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bm%7D%7Bs%7D%20%20)
The relation between speed of sound and temperature is given as :
![V = 331 \frac{m}{s} + ( 0.6 \frac{m}{s- ^0C} * T )](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%20%2B%20%28%200.6%20%5Cfrac%7Bm%7D%7Bs-%20%5E0C%7D%20%2A%20T%20%20%29%20)
Given : Temperature = 25 ⁰ C
Plugging values in formula =>
![V = 331 \frac{m}{s} + (0.6 \frac{m}{s-^0C} * 25^0C)](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%2B%20%280.6%20%5Cfrac%7Bm%7D%7Bs-%5E0C%7D%20%20%2A%2025%5E0C%29%20%20%20)
![V = 331 \frac{m}{s} + 15 \frac{m}{s}](https://tex.z-dn.net/?f=%20V%20%3D%20331%20%5Cfrac%7Bm%7D%7Bs%7D%20%2B%2015%20%5Cfrac%7Bm%7D%7Bs%7D%20%20%20)
![V = 346 \frac{m}{s}](https://tex.z-dn.net/?f=%20V%20%3D%20%20346%20%5Cfrac%7Bm%7D%7Bs%7D%20%20)
Hello!
![\large\boxed{a = 3m/s^{2}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Ba%20%3D%203m%2Fs%5E%7B2%7D%7D)
Use the following equation to solve for the average acceleration of the motorcycle:
![a = \frac{v_{f}-v_{i}}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_%7Bf%7D-v_%7Bi%7D%7D%7Bt%7D)
Plug in the given final, initial velocities, and the time:
![a = \frac{15-6}{3}\\\\a = \frac{9}{3}\\\\a = 3m/s^{2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B15-6%7D%7B3%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B9%7D%7B3%7D%5C%5C%5C%5Ca%20%3D%203m%2Fs%5E%7B2%7D)