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vitfil [10]
2 years ago
10

If 26.4 g of hydrogen, H2, is produced from 100.0 g of methane, CH4, reacting with excess water as shown, what is the percentage

yield? CH4(g) + H2O(g) → CO(g) + 3H2(g)
Chemistry
1 answer:
blondinia [14]2 years ago
6 0

Answer: Percent yield represents the ratio between what is experimentally obtained and what is theoretically calculated, multiplied by 100%.

% yield

=

actual yield

theoretical yield

⋅

100

%

So, let's say you want to do an experiment in the lab. You want to measure how much water is produced when 12.0 g of glucose (

C

6

H

12

O

6

) is burned with enough oxygen.

C

6

H

12

O

6

+

6

O

2

→

6

C

O

2

+

6

H

2

O

Since you have a

1

:

6

mole ratio between glucose and water, you can determine how much water you would get by

12.0

g glucose

⋅

1 mole glucose

180.0 g

⋅

6 moles of water

1 mole glucose

⋅

18.0 g

1 mole water

=

7.20

g

This represents your theoretical yield. If the percent yield is 100%, the actual yield will be equal to the theoretical yield. However, after you do the experiment you discover that only 6.50 g of water were produced.

Since less than what was calculated was actually produced, it means that the reaction's percent yield must be smaller than 100%. This is confirmed by

% yield

=

6.50 g

7.20 g

⋅

100

%

=

90.3

%

You can backtrack from here and find out how much glucose reacted

65.0 g of water

⋅

1 mole

18.0 g

⋅

1 mole glucose

6 moles water

⋅

180.0 g

1 mole glucose

=

10.8

g

So not all the glucose reacted, which means that oxygen was not sufficient for the reaction - it acted as a limiting reagent.

Explanation:

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kicyunya [14]
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8 0
2 years ago
Consider the market for paper. Let market demand be given by inverse demand function P d (Q) = 60 − Q, where Q is tons of paper
MakcuM [25]

Answer:

See explaination

Explanation:

Demand for paper is given below:

P(Q)=60-Q,

Number of paper mills=20

The cost curve for firm is given below:

C(Q)=10Q2

The external cost in terms of pollution down river by production of paper is given below:

EC(Q)=10Q2

a. The optimal level of paper production by market can be calcuated by equating MC=P

20Q=P

Q=P/20

b. The optimal level of paper production by market can be calcuated by equating MC=P.

MC=20Q

60-(20Q)=20Q

Q=60/40

Q=1.5

Total quanity by 20 firms will be 1.5*20=30

c. The socially efficient level of paper output is calcuated below:

MC+EC'=20Q+20Q

60-(20Q)=40Q

Q=60/60

Q=1

Total quanity by 20 firms will be 1*20=20

The price will be P=60-20=40

d, The deadweight loss occurs as market price increases and quantity decreases due to the external cost . The deadweight loss is calcuated below:

DWL=(1/2)*change in price* change in quantity

=(1/2)*10*10=50

e. 20 firms merged into one firm to make monopoly firm. The cost function for the monopoly is given below:

Cm(Q)=20*10(Q/20)2

The marginal cost for the monopoly firm will be

MCm=Q

The marginal revenue for the firm is 60-2Q

For optimal output MR is equated to MC

60-2Q=Q

Q=20

P=40.

The monopoly outcome is below the perfect competition outcome and price is higher in comparison to perfect competition. The monopoly outcome is same as socially efficient outcome.

The total surplus for this outcome is sum of consumer surplus and producer surplus and subtraction of external cost

TS=CS+PS-EC

=(1/2)*20*20+(1/2)*40*20-10(20)2

=600-4000=-3400

Due to the external effects the total surplus to the society is negative. In perfect competition this effect is not considered and output produced is high therefore, the external cost will be higher with higher output leading to higher negative social surplus. Generally the monopoly outcome reduces the total social surplus but in case of externality, the monopoly total surplus is higher than the perfect competition.

3 0
3 years ago
A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m
nata0808 [166]

A 250 ml sample of saturated a g o h solution was titrated with h c l , and the endpoint was reached after 2. 60 ml of 0. 0136 m h c l was dispensed. Based on this titration, what is the k s p of a g o h <u>. Ksp=1.9×10⁻⁸</u>

<h3>What is titration?</h3>

Titration is a typical laboratory technique for quantitative chemical analysis used to calculate the concentration of a specified analyte. It is also referred to as titrimetry and volumetric analysis (a substance to be analyzed). A standard solution with a known concentration and volume is prepared as the reagent, also known as the titrant or titrator. To ascertain the concentration of the analyte, the titrant reacts with an analyte solution (also known as the titrand). The titration volume is the amount of titrant that interacted with the analyte.

A typical titration starts with a beaker or Erlenmeyer flask being placed below a calibrated burette or chemical pipetting syringe that contains the titrant and a little amount of the indicator (such as phenolphthalein).

To learn more about titration from the given link:

brainly.com/question/186765

#SPJ4

5 0
1 year ago
A mercury thermometer is used to take four temperatures of a solution
anastassius [24]

Answer:

scale. Mercury thermometers can be used to determine body, liquid, and vapor temperature.

7 0
3 years ago
Over-encouraging lesser skilled players can lead to embarrassment.<br> a. True<br> b. False
Margarita [4]
My answer would be a. True
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3 years ago
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