1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
3 years ago
5

Radio Frequency IDentification (RFID) tags and readers are a category of low-end wireless devices that people may not recognize

as forming a computer network. Which of the statements below are true about RFID?
i. RFID technology takes many forms, used in smartcards, implants for pets, passports, library books and more
ii. with the EPC (Electronic Product Code) RFID tags are small, inexpensive devices that have a unique identifier and a small amount of memory that can be read and written by an RFID reader
iii. the tags are the intelligence in the system, analogous to base stations and access points in WiFi networks
iv. in the EPC Gen 2 Physical Layer the data is transmitted in the same way as in all other wireless situations we have seen so far
Engineering
1 answer:
Fittoniya [83]3 years ago
8 0

Answer:

See explaination.

Explanation:

Radio Frequency Identification (RFID) tags and readers uses the electromagnetic waves to identify and track the attached objects.

A tag is attached to the object which is to be identified or tracked, and reader is used to read the response and send the acknowledgement. Therefore, RFID tags and readers are used in many industries, passports, transportations and pet identification etc.

i.

RFID technology is used in smartcards, implants for pets, passports and library books to identify and track the persons, objects and pets etc.

Hence, we can say that option (i) is true.

ii.

Electronic Product Code (EPC) is a small code stored in the RFID tag. The code stored in the memory is 96 bits which are used to identify the organization which manages the data, unique number to identify the product and a number to identify the particular tag and etc.

EPC is a unique identification number, it can read and be written by the RFID reader. It is used in supply chains instead of a bar code even though expansive.

Hence, option (ii) is true.

iii.

Tags are used to identify and track the objects. It doesn’t belong to base stations and access points as a Wi-Fi networks.

Therefore, option (iii) is false.

iv.

The EPC Generation 2 RFID tag is used to improve the security by enabling the authentication features. It is not the similar way of data transmission in the other wireless situations.

Therefore, option (iv) is false.

Finally, the options (i) and (ii) are TRUE, while (iii) and (iv) are FALSE.

You might be interested in
Which of the following has led to a safer and more prosperous global community within the last century? the Bronze Age composite
sattari [20]

Answer:

The bronze age

4 0
4 years ago
Read 2 more answers
A Gaussian random voltage X volts is input to a half-wave rectifier and the output voltage is Y = Xu (X) Volts were u (x) is the
adelina 88 [10]

Answer:

Please look at attachment carefully.

7 0
4 years ago
Is there anyone who can help me with welding?
Gnoma [55]
what is it ill know your question??!!
5 0
3 years ago
The mean of 10 numbers is 9, then the sum (total) of these numbers will be​
qwelly [4]

Answer:

90

Explanation:

mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..

here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.

5 0
3 years ago
Read 2 more answers
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields
vampirchik [111]

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen  L_o = 50 mm

The final gage length L_f = 71 mm

The area = 206 mm²

maximum load  =  162,699 N

To determine the percent elongation in %, we use the formula:

\%EL = \dfrac{L_f-L_o}{L_o}\times 100

\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100

\%EL = \dfrac{21 mm}{50 \ mm}\times 100

\%EL = 0.42 \times 100

\mathbf{\%EL = 42 \%}

The percent elongation in the length of the specimen is 42%

4 0
4 years ago
Other questions:
  • 1- Design a brute-force algorithm for solving the problem below (provide pseudocode): You have a large container with storage si
    6·1 answer
  • What mark appears on frames of industrial safety glasses?
    15·1 answer
  • Two previously undeformed cylindrical specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (w
    8·1 answer
  • All of the following statements are true EXCEPT: A) air should be let out of a tire when it is hot. B) each change in outside te
    11·1 answer
  • Koch traded Machine 1 for Machine 2 when the fair market value of both machines was $60,000. Koch originally purchased Machine 1
    10·1 answer
  • Using at least 25 of the 40 vocab terms below create a Concept Map linking the terms together with meaningful descriptor arrows.
    12·1 answer
  • An ant starts at one edge of a long strip of paper that is 34.2 cm wide. She travels at 1.3 cm/s at an angle of 61◦ with the lon
    10·1 answer
  • Suppose there is a mobile application that can run in two modes: Lazy or Eager. In Lazy Mode, the execution time is 3.333 second
    11·1 answer
  • 10. Which one of the following items would you expect to find on a floor framing plan?
    6·2 answers
  • Starting with a context diagram, draw as many nested DFDs as you consider necessary to represent all the details of your times p
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!