Answer:
# -*- coding: utf-8 -*-
# Get N from the command line
import sys
N = int(sys.argv[1])
if N > 0: #N is positive
positve = list(range(N,0,-1))
print(positve)
elif N < 0: #N is negative
negative = list(range(N,0,1))
print(negative)
else:
print("Invalid in input")
Explanation:
First, you need to identify if the number entered is positive, negative or none of them, for that we use one if, one elif and one else statement:
- If the number entered (N) is greater than zero (is positive) we print a list in the range N to 0 in steps of minus one, the zero is not printed because the function range by default omits the last value
- If the previous statement was False and the number entered is smaller than zero (is negative) we print a list in the range N to 0 in steps of one, the zero is not printed because the function range by default omits the last value
- Finally, if the two previous events were false print invalid input
Answer:
(a) attached below
(b) 
(c) 
(d) 
Ω
(e) 
and 
Explanation:
Given data:
(a) Draw the power triangle for each load and for the combined load.
°
°
≅ 
≅ 
The negative sign means that the load 2 is providing reactive power rather than consuming
Then the combined load will be
(b) Determine the power factor of the combined load and state whether lagging or leading.
or in the polar form
°
The relationship between Apparent power S and Current I is
Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.
(c) Determine the magnitude of the line current from the source.
Current of the combined load can be found by
(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω
Ω
(e) Compute the magnitude of the current in each capacitor and the line current from the source.
Current flowing in the capacitor is
Line current flowing from the source is
Answer:
Final osmolarity = 866 mOsm
Explanation:
Starting cell culture medium = 320 mOsm
30 mL of 1600 mM NaOH into 1 L= (30 mL/1000) x 1600 = 48 mM
Osmolarity = osmoles / 1 L = (Mole x equivalent) / L = 48 x 2 = 96 mOsm
Feed solution = (300 mL / 1000 mL) 1500 mOsm = 450 mOsm
Total osmolarity = 320 + 96 + 450 = 866 mOsm
Hope this helps!
Answer:
DRIVERS ED is about getting a driver’s license is an exciting time for teens, but worrisome for concerned parents like you.
Explanation:
