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Rasek [7]
3 years ago
8

Solve the compound inequality. 3x − 4 > 5 or 1 − 2x ≥ 7

Engineering
1 answer:
Kaylis [27]3 years ago
3 0
X ≤ −3 or x > 3
inequality form
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The temperature at the bottom of a reservoir is TL = 280 K and the surface temperature is TH = 295 K. This temperature differenc
Tanzania [10]

a) For the thermal efficiency we have

\eta_{th} = \frac{Q_{out}}{Q_{in}} = \frac{|W|}{|Q_h|}\\\eta_{th} = \frac{|W|}{|W|+|Q_2|}

With the previously values we know that

W=8kW and Q_L = 1440/6kW (convert the min to sec)

Replacing the values

\eta_{th}=\frac{8}{8+1440/6}=\frac{1}{31}\\\eta_{th}\% = 3.225\%

b) We use the formula of carnot efficiency

\eta_{th}=1-\frac{T_l}{T_h}\\\eta_{th}\% =(1-\frac{280}{295})*100\\\eta_{th}\%=5.085\%

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3 years ago
¿Qué es la masonería?​
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3 years ago
A binary liquid system exhibits LLE at 25°C. Determine from each of the following sets of miscibility data estimates for paramet
Phoenix [80]

Answer:

(a) - A12 = A21 = 2.747

(b) - A12 = 2.148; A21 = 2.781

(c)-  A12 = 2.781; A21 = 2.148

Explanation:

(a) - x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = A21 = 2.747

(b) -  x1(a) = 0.2 |  x2(a) = 0.8 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = 2.148; A21 = 2.781

(c) -  x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.8 | x2(b) = 0.2

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = 2.781; A21 = 2.148
7 0
4 years ago
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