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pashok25 [27]
2 years ago
5

If f(1)=7f(1)=7 and f(n)=f(n-1)+2f(n)=f(n−1)+2 then find the value of f(4)f(4).

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
5 0

Answer:

Step-by-step explanation: f1 =7

f2 = 5(7) + 2 = 37

f3 = 5(37) + 2 = 27

f4 = 5(9) + 2 = 47____

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Answer:

n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247

So the answer for this case would be n=247 rounded up to the nearest integer

Step-by-step explanation:

We know that the standard deviation is :

\sigma = 80 represent the deviation

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution and the critical value would be z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247

So the answer for this case would be n=247 rounded up to the nearest integer

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3 years ago
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