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3 years ago

What is potential energy

Chemistry

1 answer:

Evgen [1.6K]3 years ago

7 0

Answer:

basically just energy held by an object because of its relation to other objects

Explanation:

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Explain how mass and energy are conserved when water evaporates.

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<span>The water molecules that are evaporationg absorb heat energy from the surrounding environment, which causes the evaporation. If 5 grams of water evaporate, then there will be 5 grams of water vapor in the air.

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Rearrange the equation for the area of a rectangle (A=l x w) to solve for length, L

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What are the spectator ions in the equation below? Select all that apply.

Licemer1 [7]

Answer:

H+ and NO3- ions

Explanation:

The Pb²+ ions react with the SO4²‐ ions to form a solid precipitate, i.e. they bond together and undergo a phase change;

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Hence, the H+ and NO3- ions are spectator ions

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3 years ago

The balanced chemical equation for the reaction between sodium chloride and silver nitrate is:

bonufazy [111]

Answer:

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1Mole of Silver Chloride and 1Mole of Sodium Nitrate

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A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL

ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

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