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mario62 [17]
3 years ago
10

I need to make 4.5L of a 1.0mol/L solution of acetic acid, HC2H3O2. What volume of concentrated 17.4 Mol/L acid do I need?

Chemistry
1 answer:
anastassius [24]3 years ago
6 0

Answer:

0.26 L

Explanation:

Data given

Volume of acetic acid (HC₂H₃O₂)  (V1) = ?

Molarity of acetic acid (HC₂H₃O₂) (M1) = 17.4 mol/L

Volume of acetic acid (HC₂H₃O₂)  (V2) = 4.5 L

Molarity of acetic acid (HC₂H₃O₂) (M2) = 1.0 mol/L

Solution:

As we diluting the concentrated acetic acid (HC₂H₃O₂)

So, Dilution formula will be used

                M1V1 = M2V2

Put values in above equation

           17.4 mol/L x V1 = 1.0 mol/L  x  4.5 L

Rearrange the above equation

             V1 = 1.0 mol/L  x  4.5 L / 17.4 mol/L

             V1 = 4.5 mol / 17.4 mol/L

             V1 = 0.26 L

So 0.26 L of acetic acid (HC₂H₃O₂) is required

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What is the pH of .0003 M of NaOH
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We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

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pOH = 3.523

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We know that the sum of pH and pOH of a solution is 14

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A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
Andreas93 [3]
<h3>Answer:</h3>

2.809 L of H₂SO₄

<h3>Explanation:</h3>

Concept tested: Moles and Molarity

In this case we are give;

Mass of solid sodium hydroxide as 13.20 g

Molarity of H₂SO₄ as 0.235 M

We are required to determine the volume of H₂SO₄ required

<h3>First: We need to write the balanced equation for the reaction.</h3>
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  • The balanced equation for the reaction is;

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

<h3>Second: We calculate the umber of moles of NaOH used </h3>
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  • Molar mass of NaOH is 40.0 g/mol
  • Therefore;

Moles of NaOH = 13.20 g ÷ 40.0 g/mol

                          = 0.33 moles

<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>
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  • Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
  • Thus, Moles of H₂SO₄ = moles of NaOH × 2

                                    = 0.33 moles × 2

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<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>
  • When given the molarity of an acid and the number of moles we can calculate the volume of the acid.
  • That is; Volume = Number of moles ÷ Molarity

In this case;

Volume of the acid = 0.66 moles ÷ 0.235 M

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Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.

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