Hello!
To solve this problem we are going to use the
Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is
4,76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
So, the mole ratio of CH₃COOH to CH₃COONa is
5,75Have a nice day!
Fermentation occur in yeast is alcoholic.
Answer:
Generally, we know that ionic compounds are formed by reaction of metals and non metals and non metals form a covalent or non ionic bonds.
<u>IONIC COMPOUDS</u>
- Iron and chlorine (FeCl2) , ( FeCl3)
- Chlorine and Lithium (LiCl)
- oxygen and calcium ( CaO)
- Potassium and Sulphur ( K2S)
<u>NON IONIC COMPOUNDS</u>
- Potassium and Calcium (covalent bond)
- Sulphur and Bromine (covalent bond)
Explanation:
Answer:
The empirical formula for the compound is C3H4O3
Explanation:
The following data were obtained from the question:
Carbon (C) = 40.92%
Hydrogen (H) = 4.58%
Oxygen (O) = 54.50%
The empirical formula for the compound can be obtained as follow:
C = 40.92%
H = 4.58%
O = 54.50%
Divide by their molar mass
C = 40.92/12 = 3.41
H = 4.58/1 = 4.58
O = 54.50/16 = 3.41
Divide by the smallest i.e 3.41
C = 3.41/3.41 = 1
H = 4.58/3.41 = 1.3
O = 3.41/3.41 = 1
Multiply through by 3 to express in whole number
C = 1 x 3 = 3
H = 1.3 x 3 = 4
O = 1 x 3 = 3
The empirical formula for the compound is C3H4O3
Answer:
50.96g
Explanation:
Given parameters:
Number of moles of H₃PO₄ = 0.52moles
Unknown:
Mass of the compound = ?
Solution:
To find the mass of the compound:
Mass = number of moles x molar mass of H₃PO₄
Molar mass of H₃PO₄ = 3(1) + 31 + 4(16) = 98g/mol
Mass = 0.52 x 98 = 50.96g
