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3 years ago

Determine the mass in grams of 0.600 mol of oxygen atoms ( 32 grams x1mole/(mass of element)

Chemistry

1 answer:

yarga [219]3 years ago

8 0

Answer:

The mass of 02 is 19,2 grams in 0,6 moles

Explanation:

1 mol 0 2------------32g

0,6mol 02-----------x= (0,6 mol 02 x 32 g)/1 mol 02 = 19,2 grams

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The pH of a solution is 5.0. To a 10 ml of this

mylen [45]

Answer:

pH = 7

Explanation:

pH is defined as -log [H⁺]. In a solution of pH 5:

pH = -log [H⁺]

10^(-5) = [H⁺]

1x10⁻⁵M = [H⁺].

Then, this solution is diluted from 10mL to 1000mL (990mL of water + 10mL of the original solution). That means the solution is diluted:

1000mL / 10mL / 100 times.

If [H⁺] before dilution was 1x10⁻⁵M, after dilution will be:

1x10⁻⁵M / 100 = 1x10⁻⁷M

And pH:

pH = -log [H⁺]

pH = -log 1x10⁻⁷M

8 0

3 years ago

Consider the reaction 2CO(g) + O2(g)2CO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

Marizza181 [45]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(CO_2(g))})]-[(1\times \Delta S^o_{(O_2(g))})+(2\times \Delta S^o_{(CO(g))})]$

We are given:

$\Delta S^o_{(CO_2(g))}=213.74J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(CO)}=197.674J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (213.74))]-[(1\times (205.14))+(2\times (197.674))]\\\\\Delta S^o_{rxn}=-173.008J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-173.008) J/K = 173.008 J/K

We are given:

Moles of CO gas reacted = 2.25 moles

By Stoichiometry of the reaction:

When 2 moles of CO is reacted, the entropy change of the surrounding will be 173.008 J/K

So, when 2.25 moles of CO is reacted, the entropy change of the surrounding will be = $\frac{173.008}{1}\times 2.25=432.52J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

3 0

4 years ago

Which of the following is not a property of an acid?

SpyIntel [72]

Answer:

1. bitter

2. turns litmus paper red

3. oxygen, hydrogen, and molecules.

Explanation:

7 0

3 years ago

Read 2 more answers

Could a mixture be made up of only elements and no compounds. explain

lbvjy [14]

Yes, because a mixture is 2 or more substances that are mixed together (not chemically). A mixture could be two different elements physically combined in a set ratio.

8 0

3 years ago

Characteristics of crystal

Orlov [11]

Answer:

Crystalline solids, or crystals, have distinctive internal structures that in turn lead to distinctive flat surfaces, or faces. The faces intersect at angles that are characteristic of the substance. When exposed to x-rays, each structure also produces a distinctive pattern that can be used to identify the material.

Explanation:

5 0

3 years ago