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Sliva [168]
3 years ago
13

Determine the mass in grams of 0.600 mol of oxygen atoms ( 32 grams x1mole/(mass of element)

Chemistry
1 answer:
yarga [219]3 years ago
8 0

Answer:

The mass of 02 is 19,2 grams in 0,6 moles

Explanation:

1 mol 0 2------------32g

0,6mol 02-----------x= (0,6 mol 02 x 32 g)/1 mol 02 = 19,2 grams

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madam [21]

The correct answer attached in file, Thank you for joining brainly community.

3 0
2 years ago
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer
lidiya [134]

The question is incomplete, the complete question is

Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V

Answer:

only IV and V

Explanation:

If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.

On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.

This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.

7 0
3 years ago
How many electrons would be found in an isotope of silicon 29
kenny6666 [7]
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5 0
4 years ago
The Center of the Adam is called
Setler [38]

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3 0
4 years ago
Read 2 more answers
Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
ExtremeBDS [4]
Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
4 0
3 years ago
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