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Studentka2010 [4]
3 years ago
7

When large amplitude sound vibrates the ear significantly,

Physics
2 answers:
miv72 [106K]3 years ago
8 0
D. Because Large amplitude is a loud sound while a Smaller Amplitude means a soft sound
tensa zangetsu [6.8K]3 years ago
5 0
Loud sounds ... d) willl  be answer
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If the absolute pressure of a gas is 550.280 kPa, its gage pressure is A. 101.325 kPa. B. 651.605 kPa. C. 448.955 kPa. D. 277.28
guajiro [1.7K]

Answer:

Option C is the correct answer.

Explanation:

Absolute  pressure is sum of gauge pressure and atmospheric pressure.

That is

               P_{abs}=P_{gauge}+P_{atm}

We have

          P_{abs}=550.280 kPa\\\\P_{atm}=1atm=101325Pa=101.325kPa

Substituting

         P_{abs}=P_{gauge}+P_{atm}\\\\550.280=P_{gauge}+101.325\\\\P_{gauge}=448.955kPa

Option C is the correct answer.

7 0
3 years ago
A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total
Aloiza [94]

Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

6 0
2 years ago
Why did Copernicus want to develop a completely new system for predicting planetary positions? Provide two reasons.
LiRa [457]

Answer:

1) improve the quality of data

2) new system is more simple and elegant

Explanation:

the reason for being selected new system of determining planetary positions are

1) he want to improve the quality of data for having new planetary positioned value.

b) he believed that new system is more simple and elegant for determining planetary positions by both skilled and unskilled user i.e. astronomers and general public

7 0
3 years ago
What is the energy (in ev) of an x-ray photon that has a wavelength of 3.1 nm ?
shepuryov [24]
Veiyxvq;ouzb1qxzbqioxzv;ux
3 0
3 years ago
your schools choir consisting of 10 singers gives a performance producing a sound intensity of 100 dB. At a point in the perform
laila [671]
There are two units of sound: intensity and in decibels. Decibels are not additive, you must convert it first to units of intensity (W/m²) using this formula:

dB = 10 log(I/10⁻¹²)

A.   100 dB = 10 log(I/10⁻¹²)
       Solving for I,
       I = 0.01 W/m²

      90 dB = 10 log(I/10⁻¹²)
      Solving for I,
       I = 0.001

Ratio = 0.01/0.001 = 10
<em>Thus,the choir is 10 times more intense than the soloist.</em>

B. Since there are 90 singers, there would be 9 groups of 10-person choir that produces 100 dB or 0.01 W/m². The total intensity would be

Total intensity = 0.01 W/m² (original choir) + 0.001 W/m² (soloist) + 10(0.01 W/m²) (additional 90 singers) = 0.111 W/m²
dB = 10 log(0.111/10⁻¹²) = <em>110.45 dB</em>

C. Rock concert:
    120 dB = 10 log(I/10⁻¹²)
    Solving for I,
    I = 1 W/m²

Ratio = 1/0.111 = 9
<em>Therefore, the rock concert is 9 times more intense than the choir concert.</em>


7 0
3 years ago
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