All categories

3 years ago

A mosquito flying at 3 m/s that encounters a breeze blowing at 3 m/s in the same direction has a speed of

Physics

1 answer:

Vika [28.1K]3 years ago

4 0

Answer:

6m/s

Explanation:

The mosquito will have a speed of 6 m/s.

if the speed of the mosquito and breeze was in opposite direction, we will subtracted them from each other and the result will be the speed of mosquito moving in the direction of the higher speed (between the breeze and mosquito). while if they are both moving in the same direction the speed of the mosquito will be the sum of both the speed of the mosquito and breeze thus the mosquito and breeze are moving in the same direction so we just sum it up (3m/s + 3m/s = 6m/s).

You might be interested in

What element is used as a lining in aprons to protect people in x rays

strojnjashka [21]

It's lead. That's why the "apron" is so heavy.

4 0

4 years ago

Swings are usually made out of materials that do not conduct heat easily, so that children will not burn themselves as they play

Irina18 [472]

the correct answer is D: all of these

8 0

3 years ago

He __________ uses a series of gears to adjust the output speed of the engine.

Verizon [17]

Hey ／人 ◕ ‿‿ ◕ 人＼
The answer is transmission

uses a series of gears to transmit power to facilitate changes in speed .

GLAD TO HELP

~~~ ╔͎═͓═͙╗
~~~ ╚̨̈́═̈́﴾ ̥̂˖̫˖̥ ̂ )

4 0

3 years ago

Example 3 :

kherson [118]

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

<h3>How to determine the friction factor</h3>

Using the formula

μ = viscosity = 0. 06 Pas

d = diameter = 120mm = 0. 12m

V = velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × $\frac{0. 06}{0. 12* 1* 0. 9}$

friction factor = 0. 52 × $\frac{0. 06}{0. 108}$

friction factor = 0. 52 × 0. 55

friction factor $= 0. 289$

b. When V = 3mls

Friction factor = 0. 52 × $\frac{0. 06}{0. 12 * 3* 0. 9}$

Friction factor = 0. 52 × $\frac{0. 06}{0. 324}$

Friction factor = 0. 52 × 0. 185

Friction factor $= 0.096$

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × $\frac{1}{2*6. 6743 * 10^-11}$ × $\frac{1^2}{0. 120}$ × $\frac{1}{100}$

Head loss = 1. 80 × 10^8

Head loss When V = 3m/s

Head loss = $0. 096$ × $\frac{1}{1. 334 *10^-10}$ × $\frac{3^2}{0. 120}$ × $\frac{1}{100}$

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

Learn more about friction here:

brainly.com/question/24338873

#SPJ1

4 0

2 years ago

Joe and Max shake hands and say goodbye. Joe walks east 0.50 km to a coffee shop, and Max flags a cab and rides north 3.45 km to

timama [110]

Answer:

3.486 km

Explanation:

Suppose Joe and Max's directions are perfectly perpendicular (east vs north). We can calculate their distance at the destinations using Pythagorean theorem:

$s = \sqrt{J^2 + M^2}$

where J = 0.5 km and M= 3.45 km are the distances between Joe and Max to their original parting point, respectively. s is the distance between them.

$s = \sqrt{0.5^2 + 3.45^2} = \sqrt{12.1525} = 3.486 km$

8 0

3 years ago