4x - 3y - 7 = 0
-3y = -4x + 7
y = 4/3x - 7/3....slope here is 4/3
A. a parallel line will have the same slope
y = mx + b
slope(m) = 4/3
(-2,1)...x = -2 and y = 1
sub and find b, the y int
1 = 4/3(-2) + b
1 = -8/3 + b
1 + 8/3 = b
3/3 + 8/3 = b
11/3 = b
so ur parallel line is : y = 4/3x + 11/3
B. A perpendicular line will have a negative reciprocal slope. To get the negative reciprocal of a number, u flip the number and change the sign. So our perpendicular line will need a slope of -3/4
y = mx + b
slope(m) = -3/4
(-2,1)...x = -2 and y = 1
sub and find b, the y int
1 = -3/4(-2) + b
1 = 3/2 + b
1 - 3/2 = b
2/2 - 3/2 = b
-1/2 = b
so ur perpendicular equation is : y = -3/4x - 1/2
Hello! To answer your question, on how much farther Payton drives than Jesse, you need to understand the needed operation for this problem. From the given problem, you can assume that 7 3/4 is a bigger fraction than Jesse's 6 3/8. Once you figure out which operation is needed to find out how much more Peyton drove, you want to make both mixed numbers into inproper fractions. To make a mixed number into an improper fraction, you multiple the whole number by the denometer and add the product to the numeratior. Think of it as going around a clock if that helps. Once they are both improper, give them both a common denometer (if needed). Once you do that, you use the operation you decided on earlier; multiplication, division, addition, or subtraction. If you have any other questions on my answer, or any information I've given, feel free to shoot me a message or another question. I hope this helped, good luck!
Answer:
-
-1
, 1.13
Step-by-step explanation:
Answer: b
Step-by-step explanation:
Answer:
Triangle JLK congruent to Triangle RTS is the only true statement
Step-by-step explanation:
AngleJKL is not corresponding to AngleRTS because AngleRTS is a right angle and AngleJKL is not.
The triangles are congruent by HL because one leg and the hypotenuse are congruent.
Triangle congruence can be determined so the third statement is incorrect.
TR is not congruent to KJ. TR=3.7 and KJ=4.5