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Alex777 [14]
3 years ago
10

What is the point used in the equation of the line y+4=1/2(x-2)

Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer:

What is the point used in the equation of the line y+4=1/2(x-2)

The other format for straight-line equations is called the "point-slope" form. For this one, they give you a point (x1, y1) and a slope m, and have you plug it into this formula:

y - y1 = m(x - x1)

Don't let the subscripts scare you. They are just intended to indicate the point they give you. You have the generic "x" and generic "y" that are always in your equation, and then you have the specific x and y from the point they gave you; the specific x and y are what is subscripted in the formula. Here's how you use the point-slope formula

They've given me m = 4, x1 = -1, and y1 = -6.  I'll plug these values into the point-slope form, and solve for "y=":

y - y1 = m(x - x1)

y - (-6) = (4)(x - (-1))

y + 6 = 4(x + 1)

y + 6 = 4x + 4

y = 4x + 4 - 6

y = 4x - 2 

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Perform the indicated operation and simplify the result.
Finger [1]

Answer:

7/ (3a-1)

Step-by-step explanation:

3a^2 -13a +4        28+7a

------------------ * --------------------

9a^2 -6a+1         a^2 -16

Factor

(3a-1)(a-4)           7(4+a)

------------------ * --------------------

(3a-1) (3a-1)        (a-4)(a+4)

Cancel like terms

1                    7

------------------ * --------------------

(3a-1)                  1

Leaving

7/ (3a-1)

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The linear combination method is the same as the elimination method.  Let's multiply the second equation by -2 so the x terms cancel each other out. When we do that we get a system of 2x-3y=13 and -2x-4y=8.  The x-terms cancel each other out giving us -7y=21 and y = -3.  Now sub -3 into one of the equations to solve for x.  x+2(-3)=-4, and x - 6 = -4.  x = 2.  So the solution for our system is (2, -3)
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