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san4es73 [151]
3 years ago
15

Doc Brown has calculated that his Delorean can accelerate at a rate of 2.52 m/s/s. How far away must he and Marty stand to allow

the car to accelerate from rest to a speed of 39.1 m/s?
Physics
1 answer:
devlian [24]3 years ago
7 0

Answer:

d = 303.33 m

Explanation:

Given that,

Acceleration of Doc Brown is 2.52 m/s²

The initial speed of Doc Brown is 0 as it was at rest.

Final speed of Doc Brown is 39.1 m/s

We need to find the distance between he and Marty. Let the distance is d. Using equation of motion as follows :

v^2-u^2=2ad\\\\\text{Put u = 0}\\\\d=\dfrac{v^2}{2a}\\\\d=\dfrac{(39.1)^2}{2\times 2.52}\\\\d=303.33\ m

So, the distance between he and Marty is 303.33 m.

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<h3>Displacement</h3>

Displacement is the distance travelled in a specified direction.

To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.

<h3>Resultant displacement of the man </h3>

In the example above, a man walks 95 km, East, then 55 km, north.

The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.

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Learn more about displacement at: brainly.com/question/321442

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