Answer:
Electron will travel to a distance of 0.189 m before its velocity is 0
Explanation:
We have initial speed of the electron
Electric field
Charge on electron will be
Mass of electron
We know that Columbus force is equal to F = qE and according to newtons law force is equal to F = ma , here m is mass and a is acceleration
These two forces will be equal
So ma = qE
According to third equation of motion
So
s = 0.189 m
So electron will travel to a distance of 0.189 m before its velocity is 0
<span>Both objects receive the same impulse.</span>
Hello
1) The work W is calculated as the product between the force F applied to the cart and the distance d covered by the cart:
2) The force is the product of the mass m of the cart and its acceleration a:
If we use this into the formula of the work, we get
3) The cart is moving by accelerated motion. For this kind of motion, we have the following relationship:
where
and
are the final and the initial velocity of the cart.
Re-arranging we have
4) Therefore, we can subsitute
into the original formula of the work, and we get
The correct answer is: <span>X, W, Y, Z
In fact, the elastic potential energy of a spring is given by
</span>
<span>where k is the spring constant and x is the stretching of the spring with respect to its rest position.
In this problem, all the four springs are stretched by the same distance x. This means that their difference in potential energy is due only to the difference between their spring constant: the larger the spring constant, the greater the energy. Therefore we can list the springs from the one with largest spring constant to the one with smallest constant, and this list corresponds to listing the springs from the one with largest energy to the one with smallest energy:
X, W, Y, Z</span>
The correct answers are: Options 2,4 and, 5
2)He solved Ptolemy’s model by proving elliptical orbits.
4)He determined that planets move faster when closer to the Sun.
5)He discovered laws of planetary motion.