Question

Write the ions present in a solution of na2co3. express your answers as chemical formulas separated by a comma. offset subscripts and charges on each ion.

Answer 1

Answer : The ions present in a solution of $Na_2CO_3$ are, $Na^+,CO_3^{2-}$

Explanation :

As we know that in an aqueous solution, the compound is dissociated into ions.

The given compound is, $Na_2CO_3$.

When $Na_2CO_3$ is dissolved in an aqueous solution then it dissociates into sodium ion $(Na^+)$ and carbonate ion $(CO_3^{2-})$.

The balanced chemical reaction will be :

$Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^{2-}(aq)$

Hence, the ions present in a solution of $Na_2CO_3$ are, $Na^+,CO_3^{2-}$

Answer 2

Na₂CO₃ → 2Na⁺ + CO₃²⁻

CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻

HCO₃⁻ + H₂O ⇄ CO₂·H₂O + OH⁻

Na⁺, CO₃²⁻, HCO₃⁻, OH⁻