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Vikentia [17]
2 years ago
9

A dry soil sample has a volume of 500 mL. After 400 mL of water are added to the soil, the soil becomes saturated with 150 mL of

surface water left on top. What is the porosity of the soil?
Please help me
Chemistry
1 answer:
Lerok [7]2 years ago
4 0
The Answer is 50. hope this helps
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How many chiral carbon atoms does the monosaccharide altrose have?
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4 In the open chain, 5 in the cyclic. Just like glucose.
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What is the change in air pressure over a given distance called? wind speed air pressure force factor air pressure gradient​
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The change in pressure over a given distance is defined as a pressure gradient. The strength of this pressure gradient determines how fast the wind moves from higher pressure toward lower pressure. A stronger pressure gradient will cause stronger winds, as shown in Figure 2. >> Balanced in the vertical by the force of gravity

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How could we separate the baking soda from the after after it had already been mixed in? helppp!!!
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7 0
2 years ago
Which of the following observations indicates that an atom has neutrons?
wel

C

When the alpha particle hits the beryllium atoms at high speeds, it splits the atomic nuclei hence causing the nuclei particles flying. When exposed to an electric field, the path of the proton is curved towards the negative pole while neutrons are unaffected.  

Explanation:

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4 0
2 years ago
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

          2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)

And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

   P_{H_{2}} = 3 \times P_{N_{2}} = 0.69 atm

Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

                        = 0.23 aatm

So, P_{NH_{3}} = 2.3 - 2(0.23)

                       = 1.84 atm

Now, expression for K_{p} will be as follows.

         K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}

           K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}

                      = \frac{0.23 \times 0.33}{3.39}

                     = 0.0224

or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

6 0
3 years ago
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