Answer:
8.324 Hope this helps! =)
It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
The loss or gain of electrons
Explanation:
The loss or gain of electrons determines if an atom will become a cation or anion.
A cation is a positively charge ion
An anion is a negatively charged ion.
In an atom, we have sub-atomic particles:
Protons are the positively charged particles
Electrons are negatively charged
Neutrons carry no charges
Only electrons can be lost or gained in chemical processes that forms cations and anions.
When a neutral atom gains electron, it has more electrons than protons. This makes it negatively charged and we call it an anion.
When a neutral atom loses an electron, the number of protons is more. We call it a cation.
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Answer:
- Empirical:

- Molecular:

Explanation:
Hello,
In this case, based on the information regarding the combustion, the moles of carbon turn out:

Moreover, the moles of hydrogen:

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

Which is hexane.
Best regards.
Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
V<span>an't
Hoff factor (i) for NaCl solution is approximately 2.
</span>Van't Hoff factor (i) for glucose solution is 1.<span>
Change in freezing point from pure solvent to
solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per
kilogram of solvent.
</span>Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.