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umka21 [38]
3 years ago
5

Below are birds-eye views of six identical toy cars moving to the right at 2 m/s. Various forces act on the cars with magnitudes

and directions indicated below. All forces act in the horizontal plane and are either parallel or at 45 or 90 degrees to the car's motion. Rank these cars on the basis of their speed a short time (ie. before any car's speed can reach zero) after the forces are applied. Rank from largest to smallest. To rank items as equivalent, overlap them.

Physics
1 answer:
Firdavs [7]3 years ago
3 0
All cars have the same speed before the forces are applied ( v = 2 m/s ).
After that rank is:
1. Largest: 6th car ;  Fr = 10 N,
2. 1st car ;  Fr = 2.95 N.
3. After that: 2nd, 3rd and 5th car ;  Fr = 0 N
4. Smallest : 4th car ;  Fr = - 2.04 N. 

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matrenka [14]

Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

T1 = 35

T2 = ?

Q = - 6.3 x 10⁴ J  = - 63000 J

Cp = 4184 J / kg°C

Formula

                        Q = mCp(T2 - T1)

                         T2 = T1 + Q/mCp    

Substitution

                       T2 = 35 - 63000/(0.5 x 4184)

                        T2 = 35 - 63000/2092

                        T2 = 35 - 30.1

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6 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
tangare [24]
The correct answer is letter A. 6 millimeters. <span>If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, the height of the image is 6 millimeters.
</span>
Solution:
18 / x = 12 / 4 
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7 0
3 years ago
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Answer:

Explanation:

A

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3 0
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Answer:

10

Explanation:

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2300/230=10

6 0
3 years ago
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