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PilotLPTM [1.2K]
3 years ago
15

Some of the earliest work on ________ was conducted by Faraday.

Physics
2 answers:
Jet001 [13]3 years ago
8 0

Answer:

C

Explanation:

Michael Faraday FRS was an English scientist who contributed to the study of electromagnetism and electrochemistry.

guajiro [1.7K]3 years ago
8 0

Answer:

A. electricity

Explanation:

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Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
3 years ago
A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 n directed at an angle of 15° below the
Kobotan [32]

Answer:

Acceleration of the crate is 0.362 m/s^2.

Explanation:

Given:

Mass of the box, m = 40 kg

Applied force, F = 15 N

Angle at which the force is applied, (\theta) = 15°

We have to find the magnitude of the acceleration.

Let the acceleration be "a".

FBD is attached with where we can see the horizontal and vertical component of force.

⇒ F_x=Fcos(\theta)          and             ⇒ F_y=Fsin (\theta)

⇒ F_x=15cos(15)                           ⇒ F_y=15sin (15)

⇒ Applying concept of  forces.

⇒ \sum F_x=F_n_e_t =F-f

⇒ F_n_e_t =F-f

⇒ ma =F-f       <em>  ...Newtons second law Fnet = ma</em>

⇒ a =\frac{F-f}{m}              

⇒ Plugging the values.

⇒ a =\frac{15cos(15)-0}{40}     <em>...f is the friction which is zero here.</em>

⇒ a =\frac{14.48}{40}

⇒ a=0.362\ ms^-^2

Magnitude of the acceleration of the crate is 0.362 m/s^2.

4 0
3 years ago
A brick is resting on a smooth wooden board that is at a 30° angle. What is one way to overcome the static friction that is hold
nata0808 [166]

Answer:

We apply force to move the brick.

Explanation:

Let me first of define a force .

A force is something applied to an object or thing to change it's internal or external state.

Now if a brick is resting on smooth wood inclined at 30° to the horizontal for us to overcome the friction which is also a force we have to apply a force greater than the gravity force acting on the body and then depending on the direction of the applied force the angle to apply it also.

3 0
3 years ago
HELP PLEASEEEEEEEEEEEEEEEE
prisoha [69]
Solid has vibrating molecules that barely move to keep it's shape

liquid moves at an average speed and keeps it's volume but not it's shape

gases move quickly and all over the place so they don't have a shape or volume

plasma is the quickest moving and is like a gas
5 0
3 years ago
A 1400-kg rocket has a net propulsion force of 20 kN (kiloNewtons). Over a short time period, it uniformly speeds up from an ini
zubka84 [21]

Answer:

  W = 8.92 10² kJ

Explanation:

For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law

        F = m a

        a = F / m

        a = 20 103/1400

        a = 14.29 m/s²

With kinematics we can find the distance traveled

      v_{f}² = v₀² + 2 a x

      x = ( v_{f}²-v₀²) / 2 a

      x = (50² -35²) / 2 14.29

      x = 1275 / 28.58

      x = 44.61 m

Let's calculate the work

      W = F.d

The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product

     W = F d

     W = 20 10³ 44.61

     W = 8.92 10⁵ J

     W = 8.92 10² kJ

6 0
3 years ago
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