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givi [52]
3 years ago
8

A series circuit contains a 100.0-Ω resistor, a 0.450-H inductor, a 0.360-µF capacitor, and a time-varying source of emf providi

ng 30.0 V.
(a) What is the resonant angular frequency of the circuit?
(b) What current will flow through the circuit at the resonant frequency?
Physics
1 answer:
eduard3 years ago
5 0

Answer:

A) The resonance angular frequency in an L-R-C circuit is

\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{0.45\times0.36\times 10^{-6}}}\\\omega_0 = 2.48\times10^3 rad/s

B) The current can be found by calculating the impedance of the system.

Z = \sqrt{R^2 + (X_L - X_C)^2} = R

Since X_L = X_C at resonance.

So, I = V/Z = V/R = 30 / 100 = 0.3A

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