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givi [52]
2 years ago
8

A series circuit contains a 100.0-Ω resistor, a 0.450-H inductor, a 0.360-µF capacitor, and a time-varying source of emf providi

ng 30.0 V.
(a) What is the resonant angular frequency of the circuit?
(b) What current will flow through the circuit at the resonant frequency?
Physics
1 answer:
eduard2 years ago
5 0

Answer:

A) The resonance angular frequency in an L-R-C circuit is

\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{0.45\times0.36\times 10^{-6}}}\\\omega_0 = 2.48\times10^3 rad/s

B) The current can be found by calculating the impedance of the system.

Z = \sqrt{R^2 + (X_L - X_C)^2} = R

Since X_L = X_C at resonance.

So, I = V/Z = V/R = 30 / 100 = 0.3A

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A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis
Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

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3 years ago
When measuring an object with a ruler, the end of the object should be lined up with the _______of the ruler.
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2 years ago
When an automobile moves with constant velocity, the power developed is used to overcome the frictional forces exerted by the ai
geniusboy [140]

Answer:

The total frictional force is 358.0 newtons

Explanation:

Power is the amount of average work (W) an object does on a period of time (Δt):

P=\frac{W}{\Delta t}

Remember average work is average force (F) times displacement (Δs):

P=\frac{F \Delta s}{\Delta t}

but displacement over time is average speed v=\frac{\Delta s}{\Delta t}, then:

P=Fv (1)

That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:

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