Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
Answer:
16
Explanation:
The magnitude of the electrostatic force between two charged particles is given by
where
k is the Coulomb's constant
q1, q2 are the charges of the two particles
r is the separation between the particles
In this problem, the initial force between the particles is F.
Later, the distance between the two particles is increased by four, so
r' = 4r
So, the new force between the particles will be
So, the new force decreases by a factor of 16.
Force on a moving charge is given by
Given that
q = 6.8 C
B = 1.4 T
angle = 15 degree
a) The magnitude will be 0.838m
b) The displacement will be -17.35°
<h3>What is displacement?</h3>
The path covered by an object from its initial point to final point.
Forces acting on the duck
x-axis: 0.13 + 0.16*cos(-56°) = 2.7 * ax
ax = 0.0813 m/s^2
y-axis: 0.13*sin(-56°) = 2.7 * ay
ay = -0.0491 m/s^2
The displacement on the x-axis
X = Vox * t + ax/2 * t²
X = 0.12* 3.2 + 0.0813/2*3.2²
X = 0.8
The displacement on the y-axis:
Y = Voy * t + ay/2 * t²
X = 0 - 0.0491/2*3.2²
Y=-0.25m
So, the magnitude and angle of this displacement [0.8,-0.25] is:
0.838m at an angle of -17.35°
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The buoyant force on the lead balloon was caused by the air molecules in the room and thus these air molecules will be hitting the surface of the balloon and those collisions will cause a force per unit area.
Answer: Option D
<u>Explanation:
</u>
The term buoyant force is exerted mostly by objects getting fully or partially immersed in a fluid. This is the upward thrusting force exerted by the fluid on the bottom of the object to prevent the complete immersion of the object.
In other words, the buoyant force helps to keep the object floating. In case of balloon in air, the air pressure acts as the fluid which will be hitting the surface of balloon.
So, these collisions will prevent the balloon to fall down and to remain floating in air with an upward push from the collision of air molecules with the surface of balloon. So, the buoyant force acts on the lead balloon by collision of air molecules with the surface of balloon and pushing it in upward direction.
