Answer:
It is not connected by any way
The first thing we need to do is figure out what equation to use. We will use the following kinematic equation...
Δx = (final velocity + initial velocity) x time / 2
We know that the car accelerates from rest, so initial velocity = 0 m/s
We also know final velocity = 20 m/s and time = 12s
Now we just need to plug everything in.
Δx = (20 x 12)/2 = 120 meters
Answer:
22kj
Explanation:
set h = 0 at the end of slide.
final height is -12m
initial condition will be Ui = 0
Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J
Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J
Ki = 1/2mv²
Ki= 1/2 x 61 x (16)² = 7808J
conservation energy says that
Ui + Ki = Uf +Kf +ΔEth
so ΔEth = Ui + Ki - Uf - Kf
ΔEth = 22234.5 - 7808 + 7173
ΔEth = 21600J
ΔEth =22Kj