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Diano4ka-milaya [45]
3 years ago
5

What happens when you decrease the pressure from 150 kPa to 50 kPa on liquid water at 100 ºC?

Chemistry
1 answer:
Tems11 [23]3 years ago
4 0
D. liquid water vaporizes. 

I have attached a phase diagram for water. As you can see, if kPa is 50, and the temperature is 100c. it is in the vapor phase.

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In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury
inysia [295]

Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

2HgO(s)⇒2Hg(l)+O₂(g)

Conservation of mass applies to a closed system, where the masses before and after the reaction are the same

mass of reactants = mass of products

mass  HgO = mass Hg + mass O₂

10 g = 9.3 g + mass O₂

mass O₂ = 0.7 g

4 0
3 years ago
How are density and state of matter related to the physical properties of a substance?
Artemon [7]

Answer:

Density by giving the object it's weight/volume. State of matter by giving its chemical substances and physical shape.

Explanation:

State of matter, (solid, liquid, or a gas) determines the main physical property of a substance. If it's a liquid, it would have an indefinite shape/physical appearance. If the object is a solid than the shape would have a definite shape/physical appearance. Density is defined as mass per volume which means the weight of an object divided by the volume determines the density of the object. You would have the volume (the amount of space an object takes up) and the mass (weight of the object) if you have the objects density.

To conclude, both density and the objects state of matter determine the physical properties of a substance. "Density the weight and volume, and the state of matter is the shape/chemical properties of the substance."

Hope this helps.

3 0
2 years ago
The chemical reaction in which solid calcium oxide is treated liquid water is an example of what: A) decomposition B)combustion
laiz [17]

Answer:

The chemical reaction in which solid calcium oxide is treated liquid water is an example of Synthesis reaction. Hence, the answer is (D) Synthesis.

Explanation:

The formula of Calcium Oxide is CaO.

The formula of liquid water is H₂O.

Calcium Oxide reacts with water and forms Calcium Hydroxide. The Chemical equation is shown below.

CaO + H₂O --> Ca(OH)₂.

This is a Synthesis reaction because Ca(OH)₂ is synthesized by using Calcium Oxide and water.

The product of this reaction is calcium hydroxide, also known as slaked lime.

Thus, when calcium oxide reacts with water, slaked lime is produced.  

Calcium oxide is also known as lime and is most commonly used for many purposes. It can be used for pH correction of water or for its disinfection (with excess lime).

8 0
3 years ago
how would you write equation to show how buffers H2CO3 and NaHCO3 behave when (a) HCl is added and (b) NaOH is added.
Vlad1618 [11]
<span>H2CO3 <---> H+ + HCO3-
NaHCO3 <---> Na+ + HCO3-

When acid is added in the buffer, the excess H+ of that acid reacts with HCO3- to form H2CO3, and due to this NaHCO3 dissociates into HCO3- to attain the equilibrium. and hence there is no net effect of H+ due to pH remain almost constant. when a base is added to the buffer, the OH- ion of base react eith H+ ion present in buffer, then to attain equilibrium of H+ ion, the H2CO3 dissociates to produce H+ ion, but now there is the excess of HCO3- due to which Na+ ion react with them to attain equilibrium of HCO3-. hence there is again no net change in H+ ion due to which pH remain constant.....</span>
8 0
3 years ago
Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The
allsm [11]

<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 8.04 days

Putting values in above equation, we get:

k=\frac{0.693}{8.04days}=0.0862days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.0862days^{-1}

t = time taken for decay process = 39 days

[A_o] = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}

[A]=0.278g

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

3 0
3 years ago
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