Answer:
a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.
Explanation:
The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).
Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.
<em>Which statement below explains that?</em>
<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.
<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.
<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.
<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.
Answer:
well idk but i will take the points
Explanation:
Answer:
7.14 × 10^(-58) m
Explanation:
We are given;
Energy; E = 2.78 x 10^(32) J
Formula to find this energy is;
E = hc/λ
Where;
E is energy
h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s
c is speed of light with a constant value of 3 × 10^(8) m/s
λ is wavelength
Making λ the subject, we have;
λ = hc/E
λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))
λ = 7.14 × 10^(-58) m
Answer:
Explanation:
For example, the energy released in burning 1 mol of octane, a component of gasoline, is about 5000 kJ.
The energy released in the fission of 1 mol of uranium-235 is
about 1.5 × 10¹⁰ kJ
.
The ratio is
The ratio of mole number of the reactants and products is equal to the coefficients. So the answer is a. 18.75 mol. b. 35.1 g. c. 1.38 * 10^5 g.
