I think the answer is 1.25 grams actually i think i’m wrong
The answer to this would be a physical change. Physical changes are changes that affect the form of a chemical substance, but not the chemical composition itself. Hope this helped!
Answer:
The answer to your question is 1.51 moles of PBr₃
Explanation:
Data
moles of Br = 2.27
moles of PBr₃ = x
Balanced chemical reaction
2P + 3Br₂ ⇒ 2PBr₃
Reactant Element Products
2 P 2
6 Br 6
-Use proportions to find the answer
3 moles of Br₂ ------------------ 2 moles of PBr₃
2.27 moles of Br₂ ------------------ x
x = (2.27 x 2) / 3
x = 4.54 / 3
x = 1.51 moles
When wood burns it makes 1 ash and 2 CO and so law of conversation matter wouldn't be violated as the ash + the smoke each would have a fraction of the original matter from the wood
Answer:
The volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L
Explanation:
Given data:
Number of moles of HF = 6.62×10⁻³ mol
Volume of HF in litter at STP = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Standard temperature = 273 K
Standard pressure = 1 atm
Now we will put the values in formula.
1 atm × V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K
V = 6.62×10⁻³mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 148.38×10⁻³ L
Thus, the volume of 6.62×10⁻³moles of HF at STP is 148.38×10⁻³ L.
