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Kipish [7]
3 years ago
15

Valence electrons determine an atom’s __________. a. mass c. atomic number b. chemical properties d. period Please select the be

st answer from the choices provided A B C D
Physics
2 answers:
shutvik [7]3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

Chemical property is defined as the property which tends to bring change in chemical composition of a substance.

For example, reactivity, combustibility, flammability, etc are all chemical properties.

And, valence electrons are the electrons present in the outermost shell of an atom. The ability of an element to lend or borrow electrons helps to determine the reactivity of an element.

Thus, we can conclude that valence electrons determine an atom’s chemical properties.

Lemur [1.5K]3 years ago
5 0
Hello,

Here is your answer:

The proper answer to this question is option B "<span>chemical properties".

Here is how:

</span>Electrons determine a atoms chemical properties mainly what its made of.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!
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A bike, a truck, and a train—all without passengers, motors, or engines—roll down the same hill. Put the vehicles in order from
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Answer:

Train Bike Truck

Explanation:

3 0
3 years ago
In the diagram, R1 = 40.0 ,
Nostrana [21]

Answer:

51 Ω.

Explanation:

We'll begin by calculating the equivalent resistance of R₁ and R₃. This can be obtained as follow:

Resistor 1 (R₁) = 40 Ω

Resistor 3 (R₃) = 70.8 Ω

Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) =?

Since the two resistors are in parallel connection, their equivalent can be obtained as follow:

R₁ₙ₃ = R₁ × R₃ / R₁ + R₃

R₁ₙ₃ = 40 × 70.8 / 40 + 70.8

R₁ₙ₃ = 2832 / 110.8

R₁ₙ₃ = 25.6 Ω

Finally, we shall determine the equivalent resistance of the group. This can be obtained as follow:

Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) = 25.6 Ω

Resistor 2 (R₂) = 25.4 Ω

Equivalent Resistance (Rₑq) =?

Rₑq = R₁ₙ₃ + R₂ (series connection)

Rₑq = 25.6 + 25.4

Rₑq = 51 Ω

Therefore, the equivalent resistance of the group is 51 Ω.

4 0
3 years ago
On a very muddy football field, a 110kg linebacker tackles an 85kg halfback. Immediately before the collision, the linebacker is
Alchen [17]
<span>Using conservation of energy and momentum you can solve this question. M_l = mass of linebacker
M_ h = mass of halfback
V_l = velocity of linebacker
V_h = velocity of halfback

So for conservation of momentum,
rho = mv

M_l x V_li + M_h x V_hi = M_l x V_lf + M_h x V_hf

For conservation of energy (kinetic)
E_k = 1/2mv^2/ 1/2mV_li^2 + 1/2mV_{hi}^2 = 1/2mV_{lf}^2 + 1/2mV_{hf}^2

Where i and h stand for initial and final values.
We are already told the masses, \[M_l = 110kg\] \[M_h = 85kg\] and the final velocities \[V_{fi} = 8.5ms^{-1}\] and \[V_{ih} = 7.2ms^{-1} </span>
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A car moving due east increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s. How far, in meters, did the car travel whil
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During the period of constant acceleration, the car's average speed is (1/2) (16 + 32) = 24 m/s. At that average speed, it covers 240 meters in 10 seconds.
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Different wavelengths of light are seen as different. A. Atoms B. Sounds C. Colors D. Speeds
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