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Kipish [7]
3 years ago
15

Valence electrons determine an atom’s __________. a. mass c. atomic number b. chemical properties d. period Please select the be

st answer from the choices provided A B C D
Physics
2 answers:
shutvik [7]3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

Chemical property is defined as the property which tends to bring change in chemical composition of a substance.

For example, reactivity, combustibility, flammability, etc are all chemical properties.

And, valence electrons are the electrons present in the outermost shell of an atom. The ability of an element to lend or borrow electrons helps to determine the reactivity of an element.

Thus, we can conclude that valence electrons determine an atom’s chemical properties.

Lemur [1.5K]3 years ago
5 0
Hello,

Here is your answer:

The proper answer to this question is option B "<span>chemical properties".

Here is how:

</span>Electrons determine a atoms chemical properties mainly what its made of.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!
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A 2kg mass is moving at 3m/s. What is its kinetic energy?
Illusion [34]
<h2><u>KINETIC ENERGY</u></h2>

<h3>Problem:</h3>

» A 2kg mass is moving at 3m/s. What is its kinetic energy?

<h3>Answer:</h3>
  • \color{hotpink} \bold{9 \: J} \\

— — — — — — — — — —

<h3>Formula:</h3>

To calculate the velocity of a kinetic energy, we can use formula

  • \underline{ \boxed{  \tt KE =  \frac{1}{2} m{v}^{2}  } }

where,

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— — —

Based on the problem, the givens are:

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<h3>Solution:</h3>

To get the velocity, substitute the givens in the formula above then solve.

\:   \: \tt KE =  \frac{1}{2} m{v}^{2}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \tt \:   KE =  \frac{1}{2} \times  2 \times {(3)}^{2}  \\ \tt  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  KE =  \frac{1}{2}  \times(2\times 9) \\ \tt  KE =  \underline{ \boxed{ \blue{ \tt9 \: J}}}

Therefore, the kinetic energy is 9 Joules.

3 0
2 years ago
A 3.2-kg thin, circular hoop with a radius of 5.4 m is rotating about an axis through its center and perpendicular to its plane.
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Torque = I × α

α = angular acceleration

I = moment of inertia

I = MR² for a circular hoop

Torque = 3.2×5.4×(– 12)

Torque = –207.4 Nm

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