Ek = 1/2mv^2
Ek = 1/2 * 30kg * 20^2 m/s
Ek = 6000J
Hope this Helps!
Answer:
The peak emf in second coil is 1.876 V
Explanation:
Given :
Inductance
H
The current 
We compare above equation with standard equation,

From above equation we have,
and 
Find the inductive resistance,



The peak emf in second coil is,


V
Therefore, the peak emf in second coil is 1.876 V
Answer:
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