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Bezzdna [24]
3 years ago
14

Please help

Chemistry
1 answer:
iragen [17]3 years ago
4 0
It is going to be neither hope this helps
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Did dalton tried to describe the atom structure?​
valentinak56 [21]

Answer:

Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties. Dalton based his theory on the law of conservation of mass and the law of constant composition. ... Parts of the theory had to be modified based on the existence of subatomic particles and isotopes.

Explanation:

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3 years ago
An oxygen atom, with 6 electrons (of a possible 8) in its outer electron shell, has the capacity to form a maximum of how many c
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Oxygen can form two covalent bonds, 
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In a titration, 45.0 mL of KOH is neutralized by 75.0 mL of 0.30M HBr. How much KOH is in 1.0 liter of the KOH solution ?
photoshop1234 [79]
KOH + HBr ---> KBr + H2O

0,3 moles of HBr ---in-------1000ml
x moles of HBr-------in------75ml
x = 0,0225 moles of HBr

according to the reaction:  1 mole of KOH = 1 mole of HBr
so
0,0225 moles of HBr = 0,0225 moles of KOH

0,0225 mole of KOH------in-----45ml
x moles of KOH -----------in------1000ml
x = 0,5 moles of KOH

answer: 0,5 mol/dm³  KOH (molarity)


8 0
3 years ago
A student has a balloon with a volume of 2.5 liters that contains 4.0 moles of air. The ballon has a small leak, allowing one mo
Over [174]

Answer:

1.9 L

Explanation:

Step 1: Given data

  • Initial number of moles of air (n₁): 4.0 mol
  • Initial volume of the balloon (V₁): 2.5 L
  • Final number of moles of air (n₂): 3.0 mol
  • Final volume of the balloon (V₂): ?

Step 2: Calculate the final volume of the balloon

According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.

V₁ / n₁ = V₂ / n₂

V₂ = V₁ × n₂ / n₁

V₂ = 2.5 L × 3.0 mol / 4.0 mol

V₂ = 1.9 L

6 0
3 years ago
Please help me. I will mark you as a brainleist.​
Tasya [4]

Answer:

<em>Your</em><em> </em><em>answer </em><em>is</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>attachment</em><em>.</em><em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em> </em><em>Stay</em><em> </em><em>blessed</em><em>.</em><em> </em>

3 0
3 years ago
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