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Andreas93 [3]
3 years ago
15

The chemical formula of glucose is C6H12O6, so it is classified as a(n)

Chemistry
2 answers:
julsineya [31]3 years ago
6 0
I think it’s classified as a sugar. The ending -ose usually means a sugar.
Rina8888 [55]3 years ago
4 0

Answer:

The answer is D. Pure Substance

Explanation:

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What is the condensed structural formula of the product of the reaction of 2,7-dimethyl-4-octene with hydrogen and a metal catal
gavmur [86]
  The  condensed  structural  formula  of the  product  of the  reaction of 2,7-dimethyl-4-octene  with hydrogen   and metal  catalyst.

 Ch3 CH(CH3) CH2 CH2 CH2 CH2 CH(CH3) CH3

Equation  is  as follows

 CH3 CH(CH3) CH2  C=C CH2 CH(CH3)  CH3  +  H2
→

CH3 CH(CH3)CH2 CH2 CH2 CH2 CH(CH3) CH3

metal catalyst  example is nickel  and the name  of structure formed is 
2,7-  dimethyl octane
6 0
3 years ago
what is the technique for testing different chemicals known as ? it says that when they were burnt, they gave off a different co
docker41 [41]

Answer:

A flame test is an analytical procedure used in chemistry to detect the presence of certain elements, primarily metal ions, based on each element's characteristic emission spectrum. The color of flames in general also depends on temperature; see flame color.

Explanation:

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4 0
3 years ago
What is the empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mo
liubo4ka [24]

The empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N ) is  C_2HN_3.

<h3>What is the empirical formula?</h3>

An empirical formula tells us the relative ratios of different atoms in a compound.

Given data:

Moles of carbon = 0.0683 mol

Moles of hydrogen = 0.0341 mol

Moles of nitrogen = 0.1024 mol

Dividing each mole using the smallest number that is divided by 0.0341 moles.

We get:

Carbon= 2

Hydrogen=1

Nitrogen=3

The empirical formula for a compound isC_2HN_3.

Learn more about empirical formula here:

brainly.com/question/14044066

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2 years ago
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gravitational potential  enrgy

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7 0
3 years ago
What mass of H₂O is formed when excess H₂ reacts with 64 g of O₂
taurus [48]

Answer: 72 g of H_2O is formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{64}{32}=2moles

2H_2+O_2(g)\rightarrow 2H_2O

As  H_2 is the excess reagent, O_2 is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of O_2 produce=  2 moles of H_2O

Thus 2 moles of O_2 will require=\frac{2}{1}\times 2=4moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=4moles\times 18g/mol=72g

Thus 72 g of H_2O is formed.

4 0
3 years ago
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