Question

Two steamrollers begin 115 mm apart and head toward each other, each at a constant speed of 1.10 m/sm/s . At the same instant, a fly that travels at a constant speed of 2.20 m/sm/s starts from the front roller of the southbound steamroller and flies to the front roller of the northbound one, then turns around and flies to the front roller of the southbound once again, and continues in this way until it is crushed between the steamrollers in a collision. What distance does the fly travel?

Answer 1

Answer:

The distance of fly travel is 115.06 m.

Explanation:

Given that,

Distance = 115 mm

Speed = 1.10 m/s

Speed of fly = 2.20 m/s

We need to calculate the relative speed

Using formula of relative speed

$v=v_{1}+v_{2}$

Put the value into the formula

$v=1.10+1.10$

$v=2.20\ m/s$

We need to calculate the time for the two steamrollers to meet each other

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{115}{2.20}$

$t=52.3\ sec$

We need to calculate the distance of fly travel

Using formula of distance

$d=vt$

Put the value into the formula

$d=2.20\times52.3$

$d=115.06\ m$

Hence, The distance of fly travel is 115.06 m.