The answer is A. 50 m/s
I took the test and completed the study guide in class and got it correct.
Use the equation PV=nRT to find no. of moles (n)
For this;
At STP
Pressure= P= 1 atm
Temperature=T = 273.16 K
Volume= V= 16.3 L = 16.3 dm³
R = 0.0821 dm³ atm K⁻¹ mol⁻¹
Now,
PV= nRT
(1)(16.3)=n(0.0821)(273.16)
n = 0.727 mol
Now, again using the same equation for
Pressure=P= 735 torr
Temperature=T= 57°C
T= 57+273 =330 K
n= 0.727 mol (form previous calculation)
R= 62.4 dm³ torr K⁻¹ mol⁻¹
Now,
PV= nRT
(735)V= (0.727)(62.4)(330)
V= 20.37 dm³
D. because they aren't mixed up evenly
Answer:
294.4 N
Explanation:
Since the hose obeys Hooke's law, the force it exerts on the balloon in the pouch is given by:
where
k is the spring constant
x is the stretching
In this problem,
k = 92.0 N/m
x = 3.20 m
Therefore, the force exerted is
Answer:
E = 1.25×10¹³ N/m²
Explanation:
Young's modulus is defined as:
E = stress / strain
E = (F / A) / (dL / L)
E = (F L) / (A dL)
Given:
F = 10 kg × 9.8 m/s² = 98 N
L = 1 m
dL = 10⁻⁵ m
A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²
Solve:
E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)
E = 1.25×10¹³ N/m²
Round as needed.