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goldfiish [28.3K]
2 years ago
13

A 2400W electric toaster is connected to a standard 120 V wall outlet. A family

Physics
1 answer:
jolli1 [7]2 years ago
5 0

Answer:

1)  energy = 15.6 kWh,  2)    total_cost = $ 2.03

Explanation:

1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is

P = 2400 W = 2,400 kW

       energy = P  t

       energy = 2,400  6.5

        energy = 15.6  kWh

using rounding to a decimal

        energy = 15.6 kWh

2) The cost of energy is unit_cost = $ 0.13 / kWh

so the total cost

         total_cost = energy    unit_cost

         total_cost = 15.6   0.13

         total_cost = $ 2.028  

rounding to two decimal places

         total_cost = $ 2.03

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What does the number, or density, of field lines on a source charge indicate?
Harrizon [31]

Hello.

The answer: C. amount of charge on the source charge

The field lines all represent the movements of field charges.  The more crowded the field lines or the more density of electric field the higher is the magnitude of the source charge.

Have a  nice day.

6 0
3 years ago
Read 2 more answers
5) A 20.0 kg cart with no friction wheels sits on a table. A light string is attached to it and runs over a low friction pulley
ella [17]

Answer:

1) Please find attached, created with Microsoft Visio

2) The acceleration of the masses connected by the light string is 0.00735 m/s²

3) The tension in the cord is 0.147 N

4) The time it would take the block to go 1.2 m to the edge of the table is approximately 18.07 s

5) The velocity of the cart as soon as it gets to the edge of the table is 0.042 m/s

Explanation:

1) Please find attached, the required free body diagram, showing the tension, weight and frictional (zero friction) forces acting on the cart and the mass created with Microsoft Visio

2) The acceleration of the masses connected by the light string is given as follows;

F = Mass, m × Acceleration, a

The mass of the truck, M = 20.0 kg

The mass attached to the string, hanging rom the pulley, m = 0.0150 kg

The force, F acting on the system = The pulling force on the cart = The tension on the cable = The weight of the hanging mass = 0.0150 × 9.8 = 0.147 N

The pulling force acting on the cart, F = M × a

∴ F = 0.147 N = 20.0 kg × a

a = 0.147 N/(20.0 kg) = 0.00735 m/s²

The acceleration of the truck = a = 0.00735 m/s²

3) The tension in the cord = F = 0.147 N

4) The time, t, it would take the block to go 1.2 m to the edge of the table is given by the kinematic equation, s = u·t + 1/2·a·t²

Where;

s = The distance to the edge of the table = 1.2 m

u = The initial velocity = 0 m/s (The cart is assumed to be initially at rest)

a = The acceleration of the cart = 0.00735 m/s²

t = The time taken

Substituting the known values, gives;

s = u·t + 1/2·a·t²

1.2 = 0 × t + 1/2 ×0.00735 × t²

1.2 = 1/2 ×0.00735 × t²

t² = 1.2/(1/2 ×0.00735) ≈ 326.5306

t = √(1.2/(1/2 ×0.00735)) ≈ 18.07

The time it would take the block to go 1.2 m to the edge of the table = t ≈ 18.07 s

5) The velocity, v, of the cart as soon as it gets to the edge of the table is given by the kinematic equation, v² = u² + 2·a·s as follows;

v² = u² + 2·a·s

u = 0 m/s

v² = 0² + 2 × 0.00735 × 1.2 = 0.001764

v = √(0.001764) = 0.042

The velocity of the cart as soon as it gets to the edge of the table = v = 0.042 m/s.

7 0
3 years ago
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One of the primary goals of the Kepler space telescope is to search for Earth-like planets. Data gathered by the telescope indic
amid [387]

Answer:

85.62 m

168.75 years

101.04 years

Explanation:

L_0 = Length of ship = 143 m

v = Velocity of ship = 0.8c

c = Speed of light

s = Distance to Boralis orbit = 135 ly

Gamma value

\gamma=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow \gamma=\dfrac{1}{\sqrt{1-\dfrac{0.8^2c^2}{c^2}}}\\\Rightarrow \gamma=1.67

Length contraction is given by

L=\dfrac{L_0}{\gamma}\\\Rightarrow L=\dfrac{143}{1.67}\\\Rightarrow L=85.62\ m

The length is 85.62 m

Time taken

t=\dfrac{s}{v}\\\Rightarrow t=\dfrac{135}{0.8}\\\Rightarrow t=168.75\ years

Time taken from the perspective one Earth is 168.75 years

Time dilation is given by

t'=\dfrac{t}{\gamma}\\\Rightarrow t'=\dfrac{168.75}{1.67}\\\Rightarrow t'=101.04\ years

The time taken from the perspective of the ship is 101.04 years

8 0
3 years ago
Which of the following best describes what went wrong with the scientists’ study? an improper experimental procedure the lack of
Rasek [7]
B- lack of control.

the scientists did not have a proper control group.
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3 years ago
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How far will a car travel in 25 seconds at 10m/ min
Kryger [21]
Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s


distance = speed × time
= 25 × (1/6)
=4.167m
7 0
3 years ago
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