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Stels [109]
3 years ago
10

A gas always spreads out to fill all available space. True or False Science Hw

Physics
2 answers:
Ira Lisetskai [31]3 years ago
7 0

This is True. Gases spread around freely and take up any available space. For example, there is oxygen. Oxygen is a gas we breathe in and spreads around freely, taking up any space.

GREYUIT [131]3 years ago
6 0

Answer:

true

Explanation:

i know this im in 6th grade

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15mph

If the man turns and runs toward point A, he will cover

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If the man runs forward toward point B, what part of the bridge

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3/8 of the bridge, only heading forward toward B. This will put

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time the train reaches A.

since we know that the man and the train will meet at B, this

means that in the time it takes the man to run the remaining

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If it takes the man the same time to cover 1/4 of the bridge

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7 0
2 years ago
Key concepts <br><br> (Example | scientific method
nekit [7.7K]
Vocabulary should be, I think: 
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What is your question exactly? 

3 0
3 years ago
Read 2 more answers
Two waves overlap producing a new wave that exhibits destructive
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Answer:B

Explanation:

8 0
3 years ago
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A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upwa
gayaneshka [121]

Answer:

F=m(11.8m/s²)

For example, if m=10,000kg, F=118,000N.

Explanation:

There are only two vertical forces acting on the rocket: the force applied from its thrusters F, and its weight mg. So, we can write the equation of motion of the rocket as:

F-mg=ma

Solving for the force F, we obtain that:

F=ma+mg=m(a+g)

Since we know the values for a (2m/s²) and g (9.8m/s²), we have that:

F= m(2m/s^{2}+9.8m/s^{2})\\\\F=m(11.8m/s^{2})

From this relationship, we can calculate some possible values for F and m. For example, if m=10,000kg, we can obtain F:

F=(10,000kg)(11.8m/s^{2})\\\\F=118,000N

In this case, the force from the rocket's thrusters is equal to 118,000N.

5 0
3 years ago
Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is
Reil [10]

Explanation:

Relation between potential energy and charge is as follows.

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Therefore, we can conclude that change in the electrical potential energy \Delta U is 1.12 \times 10^{20} J.

7 0
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