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4 years ago

Acid is added to a beaker containing crushed marble. what effect does stirring this mixture have on the system?

1 answer:

7 0

Stirring promotes the reaction by exposing all of the unreacted region of the marble to the acid. Moreover, mixing increases the degree of homogenity within the reaction mixture, meaning the reaction is carried out evenly through out rather than faster in some regions while slower in others.

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Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A

BabaBlast [244]

Answer:

For A: The energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

For B: The energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

For C: The energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

Explanation:

The relationship between energy and frequency is given by Planck's equation, which is:

$E=n\rimes N_A\times \frac{hc}{\lambda}$ ......(1)

where,

h = Planck's constant = $6.62\times 10^{-34}Js$

E = energy of the light

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of light

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

n = number of moles of photons = 1.70 moles

Conversion factor used: $1m=10^9nm$

For A:

Wavelength of infrared radiation = $1600nm=1.6\times 10^6m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

For B:

Wavelength of visible light = $505nm=5.05\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

For C:

Wavelength of ultraviolet radiation = $150nm=1.5\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J$

Hence, the energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

3 0

4 years ago

Pleaseeee help me

scoundrel [369]

Answer:

$2Al (s) + 3CuCl2( aq) --> 2AlCl3 (aq) + 3Cu(s)$

Explanation:

The main thing for this equation is to follow the amount on each side. Count each element on each side. Then by looking at the numbers figure out what numerical digit would make them equal.

For example:

On the left we have

Cu=1 and Cl=2.

But on the right we have

Cu=1 and Cl=3.

In order for them to be the same, we must add a coefficient of 3 to CuCl2 (aq0 on the left and a coefficient of 3 to Cu(s) on the right.

6 0

3 years ago

Plz do it ..i am confused

Lubov Fominskaja [6]

Answer:

.. ..

O : : C : : O

.. ..

Explanation:

8 0

3 years ago

Read 2 more answers

What is not represented by a balanced chemical equation?

astraxan [27]

Answer is: 4) The same subscripts are on each side of the equation.

For example, balanced chemical reaction:

2Mg + O₂ → 2MgO.

1) The same number of atoms is on each side of the equation: two magnesium atoms and two oxgen atoms.

2) The formulas for all substances are correct: in magnesium oxide (MgO), magnesium has oxidation number +2 and oxygen -2, so formula is good, because compound must be neutral.

3) The same mass is represented on each side of the equation: because there is same number of atoms, the mass is the same.

4) The same subscripts are on each side of the equation: oxygen does not have same subscripts.

5 0

4 years ago

The atomic weight of iodine is less than the atomic weight of tellurium. However, Mendeleev listed iodine after tellurium in his

QveST [7]

Explanation :

As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.

He placed the elements with similar nature in the same group.

According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.

As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127 and tellurium isotopes are tellurium-128 and tellurium-130.

Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

3 0

3 years ago