Answer:
the distance traveled by Charlotte in feet is 338.44 ft
Explanation:
Given;
speed of Charlotte, u = 66.5 mi/h
time of motion, t = 3.47 s
The distance traveled by Charlotte in feet is calculated as;
Therefore, the distance traveled by Charlotte in feet is 338.44 ft
Answer:
The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
shorelines of the southeast U.S.
Answer:
4
Explanation:
The weight of the rock is W = mg = (80 kg) (10 m/s²) = 800 N.
The mechanical advantage is therefore 800 N / 200 N = 4.
That it is a good one and bad one that's what I think hope it helps!:)
