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gayaneshka [121]
3 years ago
5

The velocity of an object is it’s speed and __ of motion .

Physics
2 answers:
Afina-wow [57]3 years ago
4 0
Velocity i’m pretty sure
borishaifa [10]3 years ago
3 0

Answer:

direction should be the answer

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Please answer this. Science 7th grade.
nikdorinn [45]

Answer:

the answer would be 2

Explanation:

it would be 2 because if u look at the diagram the darkest arrow is pointsin towards earth and the moon and when the moon is infront of the sun it cause's an eclispe

6 0
3 years ago
Question 7 of 25
tiny-mole [99]

Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

2Na + MgCl₂ → 2NaCl + Mg

Explanation:

A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation

Among the given chemical reactions, we have;

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

In the above reaction;

The number of phosphorus, P, on either side of the equation = 2

The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na,  one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

6 0
2 years ago
Ml(d^2θ/dt^2) =-mgθ
Nata [24]

The equation of motion of a pendulum is:

\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\dfrac{g}{\ell}\sin\theta,

where \ell it its length and g is the gravitational acceleration. Notice that the mass is absent from the equation! This is quite hard to solve, but for <em>small</em> angles (\theta \ll 1), we can use:

\sin\theta \simeq \theta.

Additionally, let us define:

\omega^2\equiv\dfrac{g}{\ell}.

We can now write:

\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\omega^2\theta.

The solution to this differential equation is:

\theta(t) = A\sin(\omega t + \phi),

where A and \phi are constants to be determined using the initial conditions. Notice that they will not have any influence on the period, since it is given simply by:

T = \dfrac{2\pi}{\omega} = 2\pi\sqrt{\dfrac{g}{\ell}}.

This justifies that the period depends only on the pendulum's length.

4 0
3 years ago
8. (-/2 Points]
gogolik [260]

Answer:

ответ семь

Explanation:

Добавить eght то девять и да

7 0
2 years ago
Is F=1/l√T/m dimentionally correct?​
kotegsom [21]

Answer:

no it is not correct dimensionally

Explanation:

f=1/l√T/m

taking square on both side in order to remove square root

f²=T/l²m

f=ma =kgm/sec²

therefore

kg.m/sec²=sec/m².kg

kg.m=sec*sec²/m².kg

kg.m=sec³/m².kg

kg=sec³/m³.kg

so the equation is incorrect dimensionally

3 0
3 years ago
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