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leonid [27]
3 years ago
8

Please help me out with this

Mathematics
2 answers:
IRINA_888 [86]3 years ago
7 0

Answer:

48

Step-by-step explanation:

central angle with arc of <y is 96

so circumference angle 48

Afina-wow [57]3 years ago
6 0

Answer:

y = 48°

Step-by-step explanation:

The angle on the circle ( the inscribed angle ) y is half of the central angle subtended by the same arc on the circle, hence

y = 0.5 × 96° = 48°

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Help with this question please
mestny [16]

Answer:

Hot dog:155 calories  Cottage cheese: 200 calories

Step-by-step explanation:

Make 2 equations ---->(y=cottage cheese, x=hot dog) 2x+3y=910, 5x+2y=1,175---> solve for one variable---> x+1.5y=910---> x=605-1.5 y-----> do for both-----> x=155, y=200

7 0
3 years ago
Find the value of a:<br> a(x+3)&lt;5x+15-x<br> a=
Vinil7 [7]

Answer:

a= 4x+15/x+3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which best describes the transformation from the graph of f(x) = x2 to the graph of
RoseWind [281]

Transformations

(x-3)...: That means the graph shifted 3 units right.

...-1: that means the graph shifted 1 unit down.

answer: 3 units right, and 1 down

8 0
2 years ago
Read 2 more answers
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
Set up and solve the following using dimensional analysis.
Softa [21]
1).  Multiply (5400 inches) by (1 foot / 12 inch) then by (1 mile / 5280 foot).

      (See explanation at the bottom)

         =      (5400 inch) x (1 foot / 12 inch) x (1 mile / 5280 foot)

         =      (5400 x 1 x 1 / 12 x 5280)  (inch - foot - mile / inch - foot) 

         =          0.0852  mile  


2).  Multiply (16 week) by (7 day/week) then by (24 hour/day)
       then by (60 minute/hour) then by (60 sec/minute).

3).  Multiply (54 yards) by (3 foot/yard) then by (1 meter/3.28 foot)
       and then by (1000 mm/meter)

4).  Multiply (36 cm/second) by (3600 second/hour) then by (1 meter/100 cm)
      then by (1 mile/1609.3 meter).

5).  Look up how many grams in a pound  ('P')
       Look up how many mL in a gallon       ('G')

      Multiply (1.09 g/mL) by ( 1 pound/ P gram) then by (1 gallon/ G mL)

6).  Multiply (32 foot/sec) by (1 meter / 3.28 foot) then by (60 sec/minute).


Each time I told you to multiply by something, it was always a fraction
where the numerator and denominator are equal, like (60 seconds/minute)
or (1 foot / 12 inch).  Since the top and bottom of the fraction are equal, the
value of the fraction is ' 1 ' , and multiplying by it doesn't change the value,
it only changes the units ... that's what this whole exercise is about.
When you multiply, KEEP the units in the product, and then, after you multiply, you can 'cancel' units out of the top and bottom of the product.
Like if you have 'feet' on top and bottom, just cross them out.  When you're done, if you did it correctly, the last unit you end up with will be the one you want.      
4 0
3 years ago
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