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kicyunya [14]
3 years ago
13

You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________

energy. Calculate it.
Physics
2 answers:
Anni [7]3 years ago
5 0

Answer:

<em>The ball has 1286.25 J of energy</em>

Explanation:

<u>Kinetic Energy</u>

Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is often expressed in Joules (J).

The volleyball of a mass m=2.1 Kg is served at v=35 m/s, calculating its kinetic energy:

\displaystyle K=\frac{1}{2}\cdot 2.1\cdot 35^2

\displaystyle K=\frac{1}{2}\cdot2.1\cdot 1225

K = 1286.25 Joule

The ball has 1286.25 J of energy

Elden [556K]3 years ago
4 0

Answer:

The ball has kinetic energy

the kinetic energy is 945 J

Explanation:

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Light is polarized by using:
maxonik [38]

Answer:

Polaroid fliter

Explanation:

light can be polarized by using Polaroid filters

Polaroid fliter are made of special material that is capable of blocking one of the two planes of vibration of an electromagnetic wave

hope this is useful--(have a good day)

8 0
3 years ago
A cat runs in a straight line. Which of the following statements about the cat's motion must be true?
alexira [117]

Answer:

I would think it's A cat runs in a straight line.

Explanation:

5 0
3 years ago
A fan blade, initially at rest, rotates with a constant acceleration of 0.029 rad/s2. What is the time interval required for it
LenKa [72]

Answer:

The time interval is  t = 21.30 \ s

Explanation:

From the question we are told that

    The constant acceleration is \alpha  = 0.029 \ rad / s^2

    The displacement is  \theta  =  6.58 \ rad

     

According to the second equation of motion we have that

    \theta  =  w_i* t  +  \frac{1}{2} *  \alpha  t^2

given that the blade started from rest

     w_i which is the initial angular velocity is 0

 So  

       \theta  = 0 +  \frac{1}{2} *  \alpha  t^2

 =>  t = \sqrt{ \frac{2 * \theta }{\alpha } }

substituting values  

=>    t = \sqrt{ \frac{2 * 6.58 }{0.029 } }

=>    t = 21.30 \ s

6 0
3 years ago
How you do this resistor in circuit question?
lawyer [7]
If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series,  R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel,  R = (R1*R2)/(R1+R2)

1.)    60 is parallel with 40 and both are then in series with 20.

60//40   = (60*40)/(60+40) = 2400/100 = 24 

Now the 24 is in series with the 20 

R = 24 + 20 = 44 ohms.

2.)    80 is in series with 40 and both are then in parallel with 40.

Solving the series,  R = 80 + 40 =120.

Parallel:   120//40  =     (120*40)/(120+40) =  4800/160 = 30 
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel  =  (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel  =  (50*50)/(50+50)  = 2500/100   = 25.

Solving the series  = 50 + 25 =75 ohms.

Cheers.
3 0
3 years ago
A harmonic oscillator starts with an amplitude of 20.0 cm. After 10.0 s, the amplitude decreases to 15.0 cm. If the linear dampi
tia_tia [17]

Answer: the amount of mass is oscillating is 34.8 kg

Explanation:

Given that;

amplitude A = 20.0 cm

time t = 10 s

amplitude decreases x = 15.0 cm

damping coefficient b = 2.00 N.s/m

amount of mass is oscillating = ?

we know that; amplitude can be expressed as;

x = Ae^-(∝t)

we substitute

15 = 20e^-∝(10)

∝ = 0.02877 s⁻¹

Hence mass m will be;

m = b/2∝

we substitute

m = (2 N.s/m) / ( 2 × 0.02877 s⁻¹)

m = 34.8 kg

Therefore the amount of mass is oscillating is 34.8 kg

4 0
3 years ago
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