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Ad libitum [116K]
3 years ago
15

A passenger in a train accelerating smoothly away from a station observes that a child’s yo-yo hanging by its string from a lugg

age rack makes a 10 degree angle from the vertical. Calculate the train’s acceleration?
Calculate the radius of a solid iron sphere that will have a terminal velocity of 100 m/s when dropped from a large height.

Density of iron is 7874 kg/m3. A sphere has Cd = .47. Use p = 1.3kgm3 for air
Physics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

1.73 m/s²

3.0 cm

Explanation:

Draw a free body diagram of the yo-yo.  There are two forces: weight force mg pulling down, and tension force T pulling up 10° from the vertical.

Sum of forces in the y direction:

∑F = ma

T cos 10° − mg = 0

T cos 10° = mg

T = mg / cos 10°

Sum of forces in the x direction:

∑F = ma

T sin 10° = ma

mg tan 10° = ma

g tan 10° = a

a = 1.73 m/s²

Draw a free body diagram of the sphere.  There are two forces: weight force mg pulling down, and air resistance D pushing up.  At terminal velocity, the acceleration is 0.

Sum of forces in the y direction:

∑F = ma

D − mg = 0

D = mg

½ ρₐ v² C A = ρᵢ V g

½ ρₐ v² C (πr²) = ρᵢ (4/3 πr³) g

3 ρₐ v² C = 8 ρᵢ r g

r = 3 ρₐ v² C / (8 ρᵢ g)

r = 3 (1.3 kg/m³) (100 m/s)² (0.47) / (8 (7874 kg/m³) (9.8 m/s²))

r = 0.030 m

r = 3.0 cm

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Answer: Where the charged object is brought near but never contacted to the object being charged, conduction charging involves making the physical connection of the charged object to the neutral object. Because charging by conduction involves contact, it is often called charging by contact.

Real life example: A positively charged aluminum plate comes into contact with a neutral metal sphere

Explanation:

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Magnetic field lines exit out of the?
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North Pole

Explanation:

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Points A [at (2, 3) m] and B [at (5, 7) m] are in a region where the electric field is uniform and given by E = (4i+3j)N/C. What
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Answer:

- 144 V

Explanation:

A = (2, 3) m = 2 i + 3 j

B = (5, 7) m = 5 i + 7 j

Displacement vector = AB = B - A = (3 i + 4 j) m

Electric field, E = (4 i + 3 j ) N/C

V = - E . AB

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Can a ratio be expressed as a percentage
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Four charges of equal magnitude q = 2.16 µC are situated as shown in the diagram below. If d = 0.88 m, find the electric potenti
Triss [41]

Answer:

<em>The total potential (magnitude only) is 11045.45 V</em>

Explanation:

<u>Electric Potential </u>

The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by

\displaystyle V=\frac{kq}{r}

Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:

\displaystyle V_1=\frac{9\cdot 10^{9}\times -2.16\cdot 10^{-6}}{0.88}=-22090.91\ V

The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical

V_2=-22090.91\ V

The potential of the topmost charge is almost equal to the above computed, is only different in the sign:

V_3=+22090.91\ V

The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':

\displaystyle V_4=\frac{9\cdot 10^{9}\times 2.16\cdot 10^{-6}}{1.76}=+11045.45 \ V

The total electric potential in A is

V=-22090.91\ V-22090.91\ V+22090.91\ V+11045.45 \ V

V=-11045.45 \ V

The total potential (magnitude only) is 11045.45 V

8 0
3 years ago
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