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Ad libitum [116K]
3 years ago
15

A passenger in a train accelerating smoothly away from a station observes that a child’s yo-yo hanging by its string from a lugg

age rack makes a 10 degree angle from the vertical. Calculate the train’s acceleration?
Calculate the radius of a solid iron sphere that will have a terminal velocity of 100 m/s when dropped from a large height.

Density of iron is 7874 kg/m3. A sphere has Cd = .47. Use p = 1.3kgm3 for air
Physics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

1.73 m/s²

3.0 cm

Explanation:

Draw a free body diagram of the yo-yo.  There are two forces: weight force mg pulling down, and tension force T pulling up 10° from the vertical.

Sum of forces in the y direction:

∑F = ma

T cos 10° − mg = 0

T cos 10° = mg

T = mg / cos 10°

Sum of forces in the x direction:

∑F = ma

T sin 10° = ma

mg tan 10° = ma

g tan 10° = a

a = 1.73 m/s²

Draw a free body diagram of the sphere.  There are two forces: weight force mg pulling down, and air resistance D pushing up.  At terminal velocity, the acceleration is 0.

Sum of forces in the y direction:

∑F = ma

D − mg = 0

D = mg

½ ρₐ v² C A = ρᵢ V g

½ ρₐ v² C (πr²) = ρᵢ (4/3 πr³) g

3 ρₐ v² C = 8 ρᵢ r g

r = 3 ρₐ v² C / (8 ρᵢ g)

r = 3 (1.3 kg/m³) (100 m/s)² (0.47) / (8 (7874 kg/m³) (9.8 m/s²))

r = 0.030 m

r = 3.0 cm

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2. Consider a conical pendulum with a bob of mass m = 77.0 kg on a string of length L = 10.0 m that makes an angle of ???? 3.00°
bekas [8.4K]

Explanation:

It is given that,

The mass of bob, m = 77 kg

Length of the string, L = 10 m

Angle made by the string with the vertical, \theta=3^{\circ}

(a) Let T is the force exerted by the string on the pendulum. At equilibrium,

T\ cos\theta=mg

T=\dfrac{mg}{cos\theta}

T=\dfrac{77\times 9.8}{cos(3)}

T = 755.63 N

The horizontal component of the force is given by,

T_H=T\ sin\theta

T_H=755.63\ sin(3)=39.54\ N

The vertical component of the force is given by,

T_V=T\ sin\theta=mg

T_V=754.59\ N

(b) Let a is the radial acceleration of the bob. It can be calculated as :

a=\dfrac{T_H}{m}

a=\dfrac{39.54\ N}{77\ kg}

a=0.51\ m/s^2

Hence, this is the required solution.

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3 years ago
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Andreas93 [3]

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Answer:

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Explanation:

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The part of the building structure, typically below grade, upon which all other construction is built is known as:________
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Answer:

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